Model 4 Working with Man, Woman, Child Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 7 EXERCISES
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The following question based on time & work topic of quantitative aptitude
(a) 3 days
(b) 1 days
(c) 2 days
(d) 4 days
The correct answers to the above question in:
Answer: (c)
Work done in two days = $1/6 × 2$
= $1/3$, remaining work = $2/3$
${M_1D_1}/W_1 = {M_2D_2}/W_2$
${3 × 2}/{1/3} = {6 × D_2}/{2/3}$
$D_2 = {3 × 2 × 2}/6$ = 2 days
Using Rule 10If food is available for 'a' days for 'A' men at a certain place and after 'b' days. 'B' men join, then the remaining food will serve total men forRequired time = ${A(a - b)}/{(A + B)}$ daysIf food is available for 'a' days for 'A' men at a certain place, and after 'b' days 'B' men leave then the remaining food will serve remaining men forRequired time = ${A(a - b)}/{(A - B)}$ days
Here, A = 3, a = 6, b = 2, B = 3
Required time = ${A(a - b)}/{(A + B)}$
= ${3(6 - 2)}/{3 + 3}$
= ${3 × 4}/6$ = 2 days
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Read more working with man woman child Based Quantitative Aptitude Questions and Answers
Question : 1
A man, a woman and a boy can together complete a piece of work in 3 days. If a man alone can do it in 6 days and a boy alone in 18 days, how long will a woman alone take to complete the work?
a) 24 days
b) 9 days
c) 21 days
d) 27 days
Answer »Answer: (b)
Work done by 1 woman in 1 day
= $1/3 - 1/6 - 1/18 = {6 - 3 - 1}/18 = 1/9$
Woman will do the work in 9 days.
Using Rule 18A, B and C can do a certain work together within 'x' days. While, any two of them can do the same work separately in 'y' and 'z' days, then in how many days can 3rd do the same work?Required time = ${xyz}/{yz - x(y + z)}$days
Here, x = 3, y = 6 and z = 18
Required time = ${xyz}/{yz - x(y + z)}$ days
= ${3 × 6 × 18}/{6 × 18 - 3(6 + 18)}$
= $324/{108 - 3 24}$
= $324/{108 - 3 × 24} = 324/36$ = 9
Question : 2
12 men and 16 boys can do a piece of work in 5 days; 13 men and 24 boys can do it in 4 days, then the ratio of the daily work done by a man to that of a boy is
a) 1 : 3
b) 2 : 1
c) 3 : 1
d) 5 : 4
Answer »Answer: (b)
Work done by 12 men + 16 boys in 5 days
≡ Work done 13 men + 24 boys in 4 days
(60 men + 80 boys)’s 1 day’s work ≡ (52 men + 96 boys)’s 1 day’s work
(60 - 52) men ≡ (96 - 80) boys
8 men ≡ 16 boys ⇒ 1 man ≡ 2 boys
∴ Required ratio = 2 : 1
Question : 3
If 3 men or 6 women can do a piece of work in 16 days, in how many days can 12 men and 8 women do the same piece of work?
a) 3 days
b) 4 days
c) 5 days
d) 2 days
Answer »Answer: (a)
3m = 6w ⇒ 1m = 2w
12m + 8w = (12 × 2w) + 8w = 32w
6 women can do the work in 16 days.
32 women can do the work in ${16 × 6}/32 = 3$ days
Using Rule 12If A men or B boys can do a certain work in 'a' days, then $A_1$ men and $B_1$ boys can do the same work inTime taken = $a/{A_1/A + B_1/B} = {a(A . B)}/{A_1B + B_1A}$ days
Here, A = 3, B = 6, a = 16, $A_1$ = 12, $B_1$ = 8
Time taken = ${a(A × B)}/{A_1B + B_1A}$
= ${16(3 × 6)}/{12 × 6 + 8 × 3}$
= ${16 × 18}/96$ = 3 days
time & work Shortcuts and Techniques with Examples
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Model 1 Basics on Time & Work
Defination & Shortcuts … -
Model 2 Formula method ‘M1D1W1 = M2D2W2’
Defination & Shortcuts … -
Model 3 Man leaves & joins
Defination & Shortcuts … -
Model 4 Working with Man, Woman, Child
Defination & Shortcuts … -
Model 5 Split & Fraction of work
Defination & Shortcuts … -
Model 6 Efficiency of the worker
Defination & Shortcuts … -
Model 7 Working with individual wages
Defination & Shortcuts …
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