Model 4  Working with Man, Woman, Child Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 7 EXERCISES

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The following question based on time & work topic of quantitative aptitude

Questions : Three men can complete a piece of work in 6 days. Two days after they started the work, 3 more men joined them. How many days will they take to complete the remaining work ?

(a) 3 days

(b) 1 days

(c) 2 days

(d) 4 days

The correct answers to the above question in:

Answer: (c)

Work done in two days = $1/6 × 2$

= $1/3$, remaining work = $2/3$

${M_1D_1}/W_1 = {M_2D_2}/W_2$

${3 × 2}/{1/3} = {6 × D_2}/{2/3}$

$D_2 = {3 × 2 × 2}/6$ = 2 days

Using Rule 10
If food is available for 'a' days for 'A' men at a certain place and after 'b' days. 'B' men join, then the remaining food will serve total men for
Required time = ${A(a - b)}/{(A + B)}$ days
If food is available for 'a' days for 'A' men at a certain place, and after 'b' days 'B' men leave then the remaining food will serve remaining men for
Required time = ${A(a - b)}/{(A - B)}$ days

Here, A = 3, a = 6, b = 2, B = 3

Required time = ${A(a - b)}/{(A + B)}$

= ${3(6 - 2)}/{3 + 3}$

= ${3 × 4}/6$ = 2 days

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Read more working with man woman child Based Quantitative Aptitude Questions and Answers

Question : 1

A man, a woman and a boy can together complete a piece of work in 3 days. If a man alone can do it in 6 days and a boy alone in 18 days, how long will a woman alone take to complete the work?

a) 24 days

b) 9 days

c) 21 days

d) 27 days

Answer: (b)

Work done by 1 woman in 1 day

= $1/3 - 1/6 - 1/18 = {6 - 3 - 1}/18 = 1/9$

Woman will do the work in 9 days.

Using Rule 18
A, B and C can do a certain work together within 'x' days. While, any two of them can do the same work separately in 'y' and 'z' days, then in how many days can 3rd do the same work?
Required time = ${xyz}/{yz - x(y + z)}$days

Here, x = 3, y = 6 and z = 18

Required time = ${xyz}/{yz - x(y + z)}$ days

= ${3 × 6 × 18}/{6 × 18 - 3(6 + 18)}$

= $324/{108 - 3 24}$

= $324/{108 - 3 × 24} = 324/36$ = 9

Question : 2

12 men and 16 boys can do a piece of work in 5 days; 13 men and 24 boys can do it in 4 days, then the ratio of the daily work done by a man to that of a boy is

a) 1 : 3

b) 2 : 1

c) 3 : 1

d) 5 : 4

Answer: (b)

Work done by 12 men + 16 boys in 5 days

≡ Work done 13 men + 24 boys in 4 days

(60 men + 80 boys)’s 1 day’s work ≡ (52 men + 96 boys)’s 1 day’s work

(60 - 52) men ≡ (96 - 80) boys

8 men ≡ 16 boys ⇒ 1 man ≡ 2 boys

∴ Required ratio = 2 : 1

Question : 3

If 3 men or 6 women can do a piece of work in 16 days, in how many days can 12 men and 8 women do the same piece of work?

a) 3 days

b) 4 days

c) 5 days

d) 2 days

Answer: (a)

3m = 6w ⇒ 1m = 2w

12m + 8w = (12 × 2w) + 8w = 32w

6 women can do the work in 16 days.

32 women can do the work in ${16 × 6}/32 = 3$ days

Using Rule 12
If A men or B boys can do a certain work in 'a' days, then $A_1$ men and $B_1$ boys can do the same work in
Time taken = $a/{A_1/A + B_1/B} = {a(A . B)}/{A_1B + B_1A}$ days

Here, A = 3, B = 6, a = 16, $A_1$ = 12, $B_1$ = 8

Time taken = ${a(A × B)}/{A_1B + B_1A}$

= ${16(3 × 6)}/{12 × 6 + 8 × 3}$

= ${16 × 18}/96$ = 3 days

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