Model 4 Time & Distance with Ratios Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 5 EXERCISES

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The following question based on time & distance topic of quantitative aptitude

Questions : A and B run a 5 km race on a round course of 400 m. If their speed are in the ratio 5 : 4, the number of times, the winner passes the other, is

(a) 2

(b) 3

(c) 5

(d) 1

The correct answers to the above question in:

Answer: (b)

The winner will pass the other, one time in covering 1600m.

Hence, the winner will pass the other 3 times in completing 5km race.

Practice time & distance (Model 4 Time & Distance with Ratios) Online Quiz

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Read more problems with ratios Based Quantitative Aptitude Questions and Answers

Question : 1

The speed of A and B are in the ratio 3 : 4. A takes 20 minutes more than B to reach a destination. In what time does A reach the destination ?

a) 2 hours

b) 2$2/3$ hours

c) 1$2/3$ hours

d) 1$1/3$ hours

Answer: (d)

Ratio of speed = 3 : 4

Ratio of time taken = 4 : 3

Let the time taken by A and B be 4x hours and 3 x hours respectively.

Then, $4x - 3x = 20/60 ⇒ x = 1/3$

Time taken by A = 4x hours

= $(4 × 1/3)$ hours = 1$1/3$ hours

Using Rule 9,

Here, $S_1 = 3x, S_2 = 4x$

$t_2 = y, t_1 = y + 20/60 = y + 1/3$

$S_1t_1 = S_2t_2$

$3x(y + 1/3) = 4xy$

3y + 1 = 4y, y = 1

∴ Time taken by A

= 1 + $1/3 = 1{1}/3$ hours

Question : 2

The ratio of length of two trains is 5 : 3 and the ratio of their speed is 6 : 5. The ratio of time taken by them to cross a pole is

a) 11 : 8

b) 25 : 18

c) 27 : 16

d) 5 : 6

Answer: (b)

Required ratio

= $5/6 : 3/5$

${30 × 5}/6 : {30 × 3}/5$ = 25 : 18

Question : 3

It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the car is :

a) 3 : 4

b) 4 : 3

c) 4 : 5

d) 3 : 5

Answer: (a)

Let the speed of train be x kmph. and the speed of car be y kmph.

Time = $\text"Distance"/ \text"Speed"$

According to the question,

$120/x + 480/y$ = 8

$15/x + 60/y$ = 1 ...(i)

and, $200/x + 400/y = 25/3$

$8/x + 16/y = 1/3$

$24/x + 48/y$ = 1 ...(ii)

From equations (i) and (ii),

$24/x + 48/y = 15/x + 60/y$

$24/x - 15/x = 60/y - 48/y$

$9/x = 12/y$

$x/y = 9/12 = 3/4$ = 3 : 4

Question : 4

A cyclist, after cycling a distance of 70 km on the second day, finds that the ratio of distance covered by him on the first two days is 4 : 5. If he travels a distance of 42 km. on the third day, then the ratio of distance travelled on the third day and the first day is :

a) 3 : 2

b) 3 : 4

c) 2 : 3

d) 4 : 3

Answer: (b)

Using Rule 1,

Distance covered on the first day

= $4/5 × 70$ = 56 km

∴ Required ratio = 42 : 56 = 3 : 4

Question : 5

A truck covers a distance of 550 metre in one minute where as a bus covers a distance of 33 km in $3/4$ hour. Then the ratio of their speeds is :

a) 2 : 3

b) 3 : 4

c) 1 : 4

d) 1 : 3

Answer: (b)

Speed of truck

= ${550\text"metre"}/{60\text"second"} = (55/6)$ m./sec.

Speed of bus

= ${33 × 1000 \text"metre"}/{3/4 × 60 × 60 \text"second"} = 440/36$ m./sec.

∴ Required ratio = $55/6 : 440/36$

= 55 × 6 : 440 = 3 : 4

Question : 6

A train starts from A at 7 a.m. towards B with speed 50 km/h. Another train starts from B at 8 a.m. with speed 60 km/h towards A. Both of them meet at 10 a.m. at C. The ratio of the distance AC to BC is

a) 5 : 4

b) 6 : 5

c) 4 : 5

d) 5 : 6

Answer: (a)

AC = Distance covered by train starting from A in 3 hours

= 50 × 3 = 150 km

BC = Distance covered by train starting from B in 2 hours

= 60 ×2 = 120 km

∴ AC : BC = 150 : 120 = 5 : 4

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