Model 5 Problems with Races Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 5 EXERCISES

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The following question based on time & distance topic of quantitative aptitude

Questions : A is twice as fast as B, and B is thrice as fast as C is. The journey covered by C in 1$1/2$ hours will be covered by A in

(a) 30 minutes

(b) 10 minutes

(c) 1 hour

(d) 15 minutes

The correct answers to the above question in:

Answer: (d)

Time taken by C = t hours

Time taken by B = $t/3$ hours

and time taken by A = $t/6$ hours

Here, t = $3/2$ hours

∴ Required time taken by A

= $3/{2/6}$ hour = $1/4$ hour

= $(1/4 × 60)$ minutes = 15 minutes

Practice time & distance (Model 5 Problems with Races) Online Quiz

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Read more problems on races Based Quantitative Aptitude Questions and Answers

Question : 1

A runs twice as fast as B and B runs thrice as fast as C. The distance covered by C in 72 minutes, will be covered by A in :

a) 24 minutes

b) 12 minutes

c) 16 minutes

d) 18 minutes

Answer: (b)

Ratio of the speed of A, B and C = 6 : 3 : 1

Ratio of the time taken

= $1/6 : 1/3$ : 1 = 1 : 2 : 6

Time taken by A

= $72/6$ =12 minutes

Question : 2

Walking at the rate of 4 kmph a man covers certain distance in 2 hrs 45 min. Running at a speed of 16.5 kmph the man will cover the same distance in how many minutes ?

a) 35 min.

b) 45 min.

c) 40 min.

d) 50 min.

Answer: (c)

2 hours 45 minutes

= $(2 + 45/60)$ hours

= $(2 + 3/4)$ hours = $11/4$ hours

Distance = Speed × Time

= 4 × $11/4$ = 11 km.

Time taken in covering 11 km at 16.5 kmph

= $11/{16.5}$ hour

= $({11 × 10 × 60}/165)$ minutes

= 40 minutes

Question : 3

In a race of 200 metres, B can give a start of 10 metres to A, and C can give a start of 20 metres to B. The start that C can give to A, in the same race, is

a) 25 metres

b) 27 metres

c) 29 metres

d) 30 metres

Answer: (c)

According to the question,

Since, When B runs 200 m metres, A runs 190 metres

When B runs 180 metres, A runs

= $190/200 × 180$ = 171 metres

When C runs 200m, B runs 180 metres.

Hence, C will give a start to A by

= 200 - 171 = 29 metres

Question : 4

A and B start running at the same time and from the same point around a circle. If A can complete one round in 40 seconds and B in 50 seconds, how many seconds will they take to reach the starting point simultaneously ?

a) 200

b) 2000

c) 90

d) 10

Answer: (a)

Required time

= LCM of 40 and 50 seconds

= 200 seconds

Question : 5

In a race of 1000 m, A can beat B by 100m. In a race of 400 m, B beats C by 40m. In a race of 500m. A will beat C by

a) 50 m

b) 60 m

c) 45 m

d) 95 m

Answer: (d)

When A runs 1000m, B runs 900m.

When A runs 500m, B runs 450 m.

Again, when B runs 400m, C runs 360 m.

When B runs 450m, C runs

= $360/400 × 450$ = 405 metres

Required distance

= 500 - 405 = 95 metres

Question : 6

A is faster than B. A and B each walk 24 km. The sum of their speeds is 7 km/hr and the sum of times taken by them is 14 hours. Then A's speed is equal to:

a) 4 km/hr.

b) 7 km/hr.

c) 5 km/hr.

d) 3 km/hr.

Answer: (a)

Let, A's speed = x kmph.

B's speed = (7 - x) kmph

Time = $\text"Distance"/ \text"Speed"$

According to the question,

$24/x + 24/{7 - x} = 14$

$24({7 - x + x}/{x(7 - x)})$ = 14

${24 × 7}/{x(7 - x)}$ = 14

x (7 - x) = 12 = 4 × 3 or 3 × 4

x (7 - x) = 4 (7 - 4) or 3 (7 - 3)

x = 4 or 3

A's speed = 4 kmph.

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