Model 3 Problems on average speed Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on time & distance topic of quantitative aptitude

Questions : A man goes from Mysore to Bangalore at a uniform speed of 40 km/hr and comes back to Mysore at a uniform speed of 60 km/hr. His average speed for the whole journey is

(a) 54 km/hr

(b) 55 km/hr

(c) 48 km/hr

(d) 50 km/hr

The correct answers to the above question in:

Answer: (c)

Using Rule 5,

Average speed

= $({2xy}/{x + y})$ kmph

= $({2 × 40 × 60}/{40 + 60})$ kmph

= 48 kmph

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Read more problems on average speed Based Quantitative Aptitude Questions and Answers

Question : 1

A train goes from Ballygunge to Sealdah at an average speed of 20 km/hour and comes back at an average speed of 30 km/hour. The average speed of the train for the whole journey is

a) 25 km/hr

b) 24 km/hr

c) 27 km/hr

d) 26 km/hr

Answer: (b)

UsingRule 5,

Required average speed

= ${2 × 30 × 20}/{30 + 20}$

[Since, Distance covered is same]

= ${2 × 30 × 20}/50 = 24$ kmph

Question : 2

A constant distance from Chennai to Bangalore is covered by Express train at 100 km/hr. If it returns to the same distance at 80 km/hr, then the average speed during the whole journey is

a) 88.98 km/hr

b) 88.89 km/hr

c) 90.20 km/hr

d) 88.78 km/hr

Answer: (b)

Using Rule 5,

If same distance are covered at two different speed of x and y kmph,

the average speed of journey = ${2xy}/{x + y}$

= $({2 × 100 × 80}/{100 + 80})$ kmph

= 88.89 kmph

Question : 3

A man goes to a place on bicycle at speed of 16 km/hr and comes back at lower speed. If the average speed is 6.4 km/hr in total journey, then the return speed (in km/hr) is :

a) 6

b) 4

c) 10

d) 8

Answer: (b)

Let the speed of cyclist while returning be x kmph.

Average speed = ${2 × 16 × x}/{16 + x}$

6.4 = ${32x}/{16 + x}$

6.4 × 16 + 6.4x = 32x

32x - 6.4x = 6.4 × 16

25.6x = 6.4 × 16

$x = {6.4 × 16}/{25.6}$ = 4 kmph.

Question : 4

A person went from A to B at an average speed of x km/hr and returned from B to A at an average speed of y km/hr. What was his average speed during the total journey ?

a) $2/{x + y}$

b) $1/x + 1/y$

c) ${x + y}/{2xy}$

d) ${2xy}/{x + y}$

Answer: (d)

Using Rule 5,

Required average speed = $({2xy}/{x + y})$ kmph

[Since, can be given as corollary If the distance between A and B be z units, then

Average speed = $\text"Totaldistance"/ \text"Time taken"$

= ${z + z}/{z/x + z/y}$

= $2/{1/x + 1/y} = 2/{{x + y}/{xy}} = {2xy}/{x + y}$

Question : 5

A man covers half of his journey at 6km/hr and the remaining half at 3km/hr. His average speed is

a) 4 km/hr

b) 3 km/hr

c) 9 km/hr

d) 4.5 km/hr

Answer: (a)

Using Rule 5,
If a bus travels from A to B with the speed x km/h and returns from B to A with the speed y km/h,then the average speed will be $({2xy}/{x + y})$

If the same distance are covered at different speed of x kmph and y kmph,

the average speed of the whole journey is given by = $({2xy}/{x + y})$ kmph.

Required average speed

= ${2 × 6 × 3}/{6 + 3} = 36/9$ = 4 kmph

Question : 6

A boy rides his bicycle 10km at an average speed of 12 km/hr and again travels 12 km at an average speed of 10 km/hr. His average speed for the entire trip is approximately :

a) 11.0 km/hr

b) 12.2 km/hr

c) 10.4 km/hr

d) 10.8 km/hr

Answer: (d)

Total distance = 10 + 12 = 22 km

Total time = $10/12 + 12/10 = 244/120$ hours

Required average speed

= $\text"Total distance"/ \text"Total time"$

= $22/{244/120} = 22/244 × 120$ = 10.8 km/hr.

Using Rule 3,
If a man travels different distances $d_1,d_2,d_3$, and so on with different speeds $s_1,s_2,s_3$, respectively then,
Average speed = $({d_1 + d_2 + d_3 + ...})/{d_1/S_1 + d_2/S_2 + d_3/S_3 + ...}$

Here, $d_1 = 10, S_1 = 12, d_2 = 12, S_2$ = 10

Average Speed = ${d_1 + d_2}/{d_1/S_1 + d_2/S_2}$

= ${10 + 12}/{10/12 + 12/10} = {22 × 120}/244$ = 10.8 km/hrs.

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