Model 3 Problems on average speed Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 5 EXERCISES
The following question based on time & distance topic of quantitative aptitude
(a) 24
(b) 25
(c) 20
(d) 22.5
The correct answers to the above question in:
Answer: (a)
Using Rule 5,
Average speed = ${2xy}/{x + y}$ kmph
= ${2 × 20 × 30}/{20 + 30}$
= ${2 × 20 × 30}/50$ = 24 kmph
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Read more problems on average speed Based Quantitative Aptitude Questions and Answers
Question : 1
A man travels 50 km at speed 25 km/h and next 40 km at 20 km/ h and there after travels 90 km at 15 km/h. His average speed is :
a) 20 kmph.
b) 15 kmph.
c) 18 kmph.
d) 25 kmph.
Answer »Answer: (c)
Total distance covered
= (50 + 40 + 90) km = 180 km
Time = $\text"Distance"/ \text"Speed"$
Total time taken
= $(50/25 + 40/20 + 90/15)$ hours
= (2 + 2 + 6) hours = 10 hours
∴ Average speed
= $\text"Total distance"/ \text"Total time taken"$
= $180/10$ = 18 kmph
Question : 2
Gautam travels 160 kms at 32 kmph and returns at 40 kmph. Then his average speed is
a) 36 kmph
b) 35.55 kmph
c) 72 kmph
d) 71.11 kmph
Answer »Answer: (b)
Here, distances are equal.
Average speed = $({2xy}/{x + y})$ kmph.
= $({2 × 32 × 40}/{32 + 40})$ kmph.
= $({2 × 32 × 40}/72)$ kmph.
= $(320/9)$ kmph. = 35.55 kmph.
Question : 3
A man covers a total distance of 100 km on bicycle. For the first 2 hours, the speed was 20 km/ hr and for the rest of the journey, it came down to 10 km/hr. The average speed will be
a) 15$1/8$ km/hr
b) 20 km/hr
c) 12$1/2$ km/hr
d) 13 km/hr
Answer »Answer: (c)
Distance covered in first 2 hours
= 2 × 20 = 40 km.
Remaining distance
= 100 - 40 = 60 km.
Time taken in covering 60 km at 10 kmph
= $60/10$ = 6 hours
∴ Required average speed
= $\text"Total distance"/ \text"Total Time"$
= $(100/{2+6})$ kmph = $(100/8)$ kmph
= $25/2$ kmph = 12$1/2$ kmph
Question : 4
To cover a distance of 216 km in 3.2 hours, what should be the average speed of the car in metre/second?
a) 37.5 metre/second
b) 18.75 metre/second
c) 67.5 metre/second
d) 33.75 metre/second
Answer »Answer: (b)
Required speed of car
= $\text"Distance"/ \text"Time"$
= $(216/{3.2})$ kmph.
= $(216/{3.2} × 5/18)$ m./sec.
= 18.75 m./sec.
Question : 5
A person travels 600 km by train at 80km/hr, 800 km by ship at 40 km/hr 500 km by aeroplane at 400 km/hr and 100 km by car at 50km/hr. What is the average speed for the entire distance ?
a) 60$5/123$ km/hr
b) 62 km/hr
c) 65$5/123$ km/hr
d) 60 km/hr
Answer »Answer: (c)
Using Rule 3,
Total time
= $600/80 + 800/40 + 500/400 + 100/50$
= $246/8$ hours.
Average speed
= ${600 + 800 + 500 +100}/{246/8}$
= ${2000 × 8}/246 = 65{5}/123$ km/hr.
Question : 6
Durga walks 5 km from her home to school in 60 minutes, then bicycles back to home along the same route at 15 km per hour. Her sister Smriti makes the same round trip, but does so at half of Durga's average speed. How much time does Smriti spend on her round trip ?
a) 160 minutes
b) 80 minutes
c) 120 minutes
d) 40 minutes
Answer »Answer: (a)
Durga's average speed
= $({2xy}/{x + y})$ kmph.
= $({2 × 5 × 15}/{5 + 15})$ kmph.
= $({2 × 5 × 15}/20)$ kmph = $15/2$ kmph
Distance of School = 5 km.
Smriti's speed = $15/4$ kmph
∴ Required time = $2(5/{15/4})$ hours
= $({2 × 5 × 4}/15) = 8/3$ hours
= $(8/3 × 60)$ minutes = 160 minutes
GET time & distance PRACTICE TEST EXERCISES
Model 1 Basic Time & Distance using formula
Model 2 Vehicles in x/y of its usual speed
Model 3 Problems on average speed
Model 4 Time & Distance with Ratios
Model 5 Problems with Races
time & distance Shortcuts and Techniques with Examples
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Model 1 Basic Time & Distance using formula
Defination & Shortcuts … -
Model 2 Vehicles in x/y of its usual speed
Defination & Shortcuts … -
Model 3 Problems on average speed
Defination & Shortcuts … -
Model 4 Time & Distance with Ratios
Defination & Shortcuts … -
Model 5 Problems with Races
Defination & Shortcuts …
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