Model 3 Problems on average speed Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 5 EXERCISES
The following question based on time & distance topic of quantitative aptitude
(a) 160 minutes
(b) 80 minutes
(c) 120 minutes
(d) 40 minutes
The correct answers to the above question in:
Answer: (a)
Durga's average speed
= $({2xy}/{x + y})$ kmph.
= $({2 × 5 × 15}/{5 + 15})$ kmph.
= $({2 × 5 × 15}/20)$ kmph = $15/2$ kmph
Distance of School = 5 km.
Smriti's speed = $15/4$ kmph
∴ Required time = $2(5/{15/4})$ hours
= $({2 × 5 × 4}/15) = 8/3$ hours
= $(8/3 × 60)$ minutes = 160 minutes
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Read more problems on average speed Based Quantitative Aptitude Questions and Answers
Question : 1
A person travels 600 km by train at 80km/hr, 800 km by ship at 40 km/hr 500 km by aeroplane at 400 km/hr and 100 km by car at 50km/hr. What is the average speed for the entire distance ?
a) 60$5/123$ km/hr
b) 62 km/hr
c) 65$5/123$ km/hr
d) 60 km/hr
Answer »Answer: (c)
Using Rule 3,
Total time
= $600/80 + 800/40 + 500/400 + 100/50$
= $246/8$ hours.
Average speed
= ${600 + 800 + 500 +100}/{246/8}$
= ${2000 × 8}/246 = 65{5}/123$ km/hr.
Question : 2
To cover a distance of 216 km in 3.2 hours, what should be the average speed of the car in metre/second?
a) 37.5 metre/second
b) 18.75 metre/second
c) 67.5 metre/second
d) 33.75 metre/second
Answer »Answer: (b)
Required speed of car
= $\text"Distance"/ \text"Time"$
= $(216/{3.2})$ kmph.
= $(216/{3.2} × 5/18)$ m./sec.
= 18.75 m./sec.
Question : 3
A train runs from Howrah to Bandel at an average speed of 20 km/ hr and returns at an average speed of 30 km/hr. The average speed (in km/hr) of the train in the whole journey is
a) 24
b) 25
c) 20
d) 22.5
Answer »Answer: (a)
Using Rule 5,
Average speed = ${2xy}/{x + y}$ kmph
= ${2 × 20 × 30}/{20 + 30}$
= ${2 × 20 × 30}/50$ = 24 kmph
Question : 4
A motorist travels to a place 150 km away at an average speed of 50 km/hr and returns at 30 km/ hr. His average speed for the whole journey in km/hr is
a) 35
b) 40
c) 37.5
d) 37
Answer »Answer: (c)
Using Rule 5,
Average speed of whole journey
= $({2xy}/{x + y})$ kmph
= ${2 × 50 × 30}/{50 + 30}$
= ${2 × 50 × 30}/80$ = 37.5 kmph
Question : 5
A train runs at an average speed of 75 km/hr. If the distance to be covered is 1050 kms, how long will the train take to cover it ?
a) 15 hrs
b) 14 hrs
c) 13 hrs
d) 12 hrs
Answer »Answer: (b)
Using Rule 1,Distance = Speed × TimeSpeed = $\text"Distance"/\text"Time"$ , Time = $\text"Distance"/\text"Speed"$1 m/s = $18/5$ km/h, 1 km/h = $5/18$ m/s
Time = $\text"Distance"/\text"Speed"$
= $1050/75$ = 14 hours
Question : 6
At an average of 80 km/hr Shatabdi Express reaches Ranchi from Kolkata in 7 hrs. The distance between Kolkata and Ranchi is
a) 560 m.
b) 650 m.
c) 560 km.
d) 506 km.
Answer »Answer: (c)
Distance = Speed × Time
= (80 × 7) km. = 560 km.
GET time & distance PRACTICE TEST EXERCISES
Model 1 Basic Time & Distance using formula
Model 2 Vehicles in x/y of its usual speed
Model 3 Problems on average speed
Model 4 Time & Distance with Ratios
Model 5 Problems with Races
time & distance Shortcuts and Techniques with Examples
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Model 1 Basic Time & Distance using formula
Defination & Shortcuts … -
Model 2 Vehicles in x/y of its usual speed
Defination & Shortcuts … -
Model 3 Problems on average speed
Defination & Shortcuts … -
Model 4 Time & Distance with Ratios
Defination & Shortcuts … -
Model 5 Problems with Races
Defination & Shortcuts …
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