Model 3 Problems on average speed Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 5 EXERCISES

Top 10,000+ Aptitude Memory Based Exercises

The following question based on time & distance topic of quantitative aptitude

Questions : A train travelled at a speed of 35 km/hr for the first 10 minutes and at a speed of 20 km/hr for the next 5 minutes. The average speed of the train for the total 15 minutes is

(a) 31 km/hr

(b) 29 km/hr

(c) 30 km/hr

(d) 23 km/hr

The correct answers to the above question in:

Answer: (c)

Using Rule 2,
If a man travels different distances $d_1,d_2,d_3$,... and so on in different time $t_1,t_2,t_3$ respectively then,Average speed
= $\text"total travelled distance"/\text"total time taken in travelling distance"$
= ${d_1 + d_2 + d_3 +...}/{t_1 + t_2 + t_3 +...}$

Distance covered

= $(35 × 10/60 + 20 × 5/60)$ km

= $(35/6 + 10/6) = 45/6$ km

Total time = 15 minutes

= $1/4$ hour

Required average speed

= $\text"Distance covered"/ \text"Time taken"$

= $45/6 × 4$ = 30 kmph

Practice time & distance (Model 3 Problems on average speed) Online Quiz

Discuss Form

Valid first name is required.
Please enter a valid email address.
Your genuine comment will be useful for all users! Each and every comment will be uploaded to the question after approval.

Read more problems on average speed Based Quantitative Aptitude Questions and Answers

Question : 1

A man goes from A to B at a uniform speed of 12 kmph and returns with a uniform speed of 4 kmph His average speed (in kmph) for the whole journey is :

a) 6

b) 4.5

c) 8

d) 7.5

Answer: (a)

Using Rule 5,

If two equal distances are covered at two unequal speed of x kmph and y kmph,

then average speed = $({2xy}/{x + y})$

= ${2 × 12 × 4}/{12 + 4} = 96/16$ = 6 kmph

Question : 2

A car completed a journey of 400 km in 12$1/2$ hrs. The first $3/4$th of the journey was done at 30 km/hr. Calculate the speed for the rest of the journey.

a) 40 km/hr

b) 30 km/hr

c) 45 km/hr

d) 25 km/hr

Answer: (a)

Total distance covered = 400 km.

Total time = $25/2$ hours

$3/4$th of total journey

= $3/4$ × 400 = 300 km.

Time taken = $\text"Distance"/ \text"Speed"$

= $300/30$ = 10 hours

Remaining time = $25/2$ –10

= ${25 - 20}/2 = 5/2$ hours

Remaining distance = 100 km.

∴ Required speed of car

= $100/{5/2} = {100 × 2}/5$ = 40 kmph.

Question : 3

A man goes from a place A to B at a speed of 12 km/hr and returns from B to A at a speed of 18 km/hr. The average speed for the whole journey is

a) 15$1/2$ km/hr

b) 16 km/hr

c) 14$2/5$ km/hr

d) 15 km/hr

Answer: (c)

Using Rule 5,

Average speed

= $({2xy}/{x + y})$ kmph

= $({2 × 12 × 18}/{12 + 18})$ kmph

= $({2 × 12 × 18}/30)$ kmph

= 14$2/5$ kmph

Question : 4

With an average speed of 40 km/ hr, a train reaches its destination in time. If it goes with an average speed of 35 km/hr, it is late by 15 minutes. The total journey is

a) 70 km

b) 80 km

c) 30 km

d) 40 km

Answer: (a)

Let the length of journey be x km, then

$x/35 - x/40 = 15/60 = 1/4$

${8x - 7x}/280 = 1/4$

$x = 280/4 = 70$ km

Question : 5

Gautam goes to office at a speed of 12 kmph and returns home at 10 kmph. His average speed is :

a) 10.9 kmph

b) 12.5 kmph

c) 11 kmph

d) 22 kmph

Answer: (a)

Here distances are same.

∴ Average speed = $({2xy}/{x + y})$ kmph

= $({2 × 12 × 10}/{12 + 10})$ kmph

= $(240/22)$ kmph = 10.9 kmph

Question : 6

A train travels 500 m in first minute. In the next 4 minutes, it travels in each minute 125 m more than that in the previous minute. The average speed per hour of the train during those 5 minutes will be

a) 50 km/hr

b) 55 km/hr

c) 30 km/hr

d) 45 km/hr

Answer: (d)

Using Rule 2,
If a man travels different distances $d_1,d_2,d_3$,... and so on in different time $t_1,t_2,t_3$ respectively then,Average speed
= $\text"total travelled distance"/\text"total time taken in travelling distance"$
= ${d_1 + d_2 + d_3 +...}/{t_1 + t_2 + t_3 +...}$

Total distance covered by train in 5 minutes

= (500 + 625 + 750 + 875 + 1000) metre

= 3750 metre = 3.75 km.

Time = 5 minutes

= $5/60$ hour = $1/12$ hour

Speed of train = Distance Time

= $(3.75/{1/12})$ kmph

= (3.75 × 12) kmph = 45 kmph

Recently Added Subject & Categories For All Competitive Exams

100+ Quadratic Equation Questions Answers PDF for Bank

Quadratic Equation multiple choice questions with detailed answers for IBPS RRB SO. more than 250 Attitude practice test exercises for all competitive exams

03-Jul-2024 by Careericons

Continue Reading »

IBPS Aptitude Linear Equations MCQ Questions Answers PDF

Linear equations multiple choice questions with detailed answers for IBPS RRB SO. more than 250 Attitude practice test exercises for all competitive exams

03-Jul-2024 by Careericons

Continue Reading »

New 100+ Compound Interest MCQ with Answers PDF for IBPS

Compound Interest verbal ability questions and answers solutions with PDF for IBPS RRB PO. Aptitude Objective MCQ Practice Exercises all competitive exams

02-Jul-2024 by Careericons

Continue Reading »

100+ Mixture and Alligation MCQ Questions PDF for IBPS

Most importantly Mixture and Alligation multiple choice questions and answers with PDF for IBPS RRB PO. Aptitude MCQ Practice Exercises all Bank Exams

02-Jul-2024 by Careericons

Continue Reading »