Model 3 Problems on average speed Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on time & distance topic of quantitative aptitude

Questions : Gautam goes to office at a speed of 12 kmph and returns home at 10 kmph. His average speed is :

(a) 10.9 kmph

(b) 12.5 kmph

(c) 11 kmph

(d) 22 kmph

The correct answers to the above question in:

Answer: (a)

Here distances are same.

∴ Average speed = $({2xy}/{x + y})$ kmph

= $({2 × 12 × 10}/{12 + 10})$ kmph

= $(240/22)$ kmph = 10.9 kmph

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Read more problems on average speed Based Quantitative Aptitude Questions and Answers

Question : 1

With an average speed of 40 km/ hr, a train reaches its destination in time. If it goes with an average speed of 35 km/hr, it is late by 15 minutes. The total journey is

a) 70 km

b) 80 km

c) 30 km

d) 40 km

Answer: (a)

Let the length of journey be x km, then

$x/35 - x/40 = 15/60 = 1/4$

${8x - 7x}/280 = 1/4$

$x = 280/4 = 70$ km

Question : 2

A train travelled at a speed of 35 km/hr for the first 10 minutes and at a speed of 20 km/hr for the next 5 minutes. The average speed of the train for the total 15 minutes is

a) 31 km/hr

b) 29 km/hr

c) 30 km/hr

d) 23 km/hr

Answer: (c)

Using Rule 2,
If a man travels different distances $d_1,d_2,d_3$,... and so on in different time $t_1,t_2,t_3$ respectively then,Average speed
= $\text"total travelled distance"/\text"total time taken in travelling distance"$
= ${d_1 + d_2 + d_3 +...}/{t_1 + t_2 + t_3 +...}$

Distance covered

= $(35 × 10/60 + 20 × 5/60)$ km

= $(35/6 + 10/6) = 45/6$ km

Total time = 15 minutes

= $1/4$ hour

Required average speed

= $\text"Distance covered"/ \text"Time taken"$

= $45/6 × 4$ = 30 kmph

Question : 3

A man goes from A to B at a uniform speed of 12 kmph and returns with a uniform speed of 4 kmph His average speed (in kmph) for the whole journey is :

a) 6

b) 4.5

c) 8

d) 7.5

Answer: (a)

Using Rule 5,

If two equal distances are covered at two unequal speed of x kmph and y kmph,

then average speed = $({2xy}/{x + y})$

= ${2 × 12 × 4}/{12 + 4} = 96/16$ = 6 kmph

Question : 4

A train travels 500 m in first minute. In the next 4 minutes, it travels in each minute 125 m more than that in the previous minute. The average speed per hour of the train during those 5 minutes will be

a) 50 km/hr

b) 55 km/hr

c) 30 km/hr

d) 45 km/hr

Answer: (d)

Using Rule 2,
If a man travels different distances $d_1,d_2,d_3$,... and so on in different time $t_1,t_2,t_3$ respectively then,Average speed
= $\text"total travelled distance"/\text"total time taken in travelling distance"$
= ${d_1 + d_2 + d_3 +...}/{t_1 + t_2 + t_3 +...}$

Total distance covered by train in 5 minutes

= (500 + 625 + 750 + 875 + 1000) metre

= 3750 metre = 3.75 km.

Time = 5 minutes

= $5/60$ hour = $1/12$ hour

Speed of train = Distance Time

= $(3.75/{1/12})$ kmph

= (3.75 × 12) kmph = 45 kmph

Question : 5

When Alisha goes by car at 50 kmph, she reaches her office 5 minutes late. But when she takes her motorbike, she reaches 3 minutes early. If her office is 25 kms away, what is the approximate average speed at which she rides her motorbike ?

a) 58 kmph

b) 52 kmph

c) 68 kmph

d) 62 kmph

Answer: (c)

Difference of time

= 5 + 3 = 8 minutes

= $8/60$ hour = $2/15$ hour

If the speed of motorbike be x kmph, then

$25/50 - 25/x = 2/15$

$25/x = 1/2 - 2/15$

$25/x = {15 - 4}/30 = 11/30$

11x = 25 × 30

$x = {25 × 30}/11 = 750/11$

= 68.18 kmph ≈ 68 kmph

Question : 6

A car travels from A to B at the rate of 40 km/h and returns from B to A at the rate of 60 km/ h. Its average speed during the whole journey is

a) 45 km/h

b) 60 km/h

c) 48 km/h

d) 50 km/h

Answer: (c)

Here, distance is same.

Average speed = ${2xy}/{x + y}$

= $({2 × 40 × 60}/{40 + 60})$ kmph.

= $({2 × 40 × 60}/100)$ kmph.

= 48 kmph.

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