Model 3 Simplification based on cube & cube root Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 4 EXERCISES
The following question based on simplification topic of quantitative aptitude
(a) 7
(b) 2
(c) 5
(d) 3
The correct answers to the above question in:
Answer: (a)
1323 = 3 × 3 × 3 × 7 × 7
It must be multiplied by 7.
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Read more problems based on cubes and roots Based Quantitative Aptitude Questions and Answers
Question : 1
The sum of the digits of the smallest number which, when multiplied by 1800, gives a perfect cube, is :
a) 8
b) 2
c) 6
d) 3
Answer »Answer: (c)
1800 = 2 × 2 × 2 × 3 × 3 × 5 × 5 = $2^3 × 3^2 × 5^2$
To make 1800 a perfect cube, it must be multiplied by 15 (least number).
>∴ Required sum = 1 + 5 = 6
Question : 2
The smallest natural number, by which 3000 must be divided to make the quotient a perfect cube, is :
a) 6
b) 3
c) 5
d) 4
Answer »Answer: (b)
3000 = 3 × 1000 = 3 × $10^3$
Clearly, when we divide 3000 by natural number 3, the quotient is 1000 which is a perfect cube.
Question : 3
Which smallest number must be added to 710 so that the sum is a perfect cube ?
a) 21
b) 29
c) 11
d) 19
Answer »Answer: (d)
Clearly, $√^3{729} = 9$
∴ 19 should be added to 710 to get a perfect cube.
Question : 4
If $√^3{3^n}$ = 27, then the value of n is :
a) 3
b) 9
c) 1
d) 6
Answer »Answer: (b)
$√^3{3^n}$ = 27
$(3)^{n/3} = 3^3$
$n/3$ = 3 ⇒ n = 3 × 3 = 9
GET simplification PRACTICE TEST EXERCISES
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Model 3 Simplification based on cube & cube root
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