model 3 based on positive and negative exponent Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 5 EXERCISES
The following question based on power, indices and surds topic of quantitative aptitude
(a) 2
(b) - 2
(c) - 1
(d) 0
The correct answers to the above question in:
Answer:(b)
$2^{x+4} - 2^{x+2}$ = 3
$2^{x+2}(2^2 - 1)$ = 3
$2^{x+2}$× 3 = 3
$2^{x+2}$ = 1 = 2°
x + 2 = 0 ⇒ x = - 2
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Read more positive and negative exponent Based Quantitative Aptitude Questions and Answers
Question : 1
Arranging the following in ascending order $3^34, 2^51, 7^17$ we get
a) $7^17 > 2^51 > 3^34$
b) $2^51 > 3^34 > 7^17$
c) $3^34 > 7^17 > 2^51$
d) $3^34 > 2^51 > 7^17$
Answer »Answer:(d)
$3^34 = (3^2)^17 = 9^17$
$2^51 = (2^3)^17 = 8^17$
$7^17 = 7^17$
Clearly, $9^17 > 8^17 > 7^17$
i.e., $3^34 > 2^51 > 7^17$
Question : 2
The unit digit in the product $(2467)^153 × (341)^72$ is
a) 3
b) 1
c) 9
d) 7
Answer »Answer:(d)
$7^1 = 7, 7^2 = 49, 7^3$ = 343,
$7^4 = 2401, 7^5$ = 16807
i.e. after index 4, the unit's digit is repeated.
On dividing 153 by 4, remainder = 1
Unit's digit in the expansion of $(2467)^153=7^1$=7 and unit's digit in the expansion of $(341)^72$ = 1
Required unit's digit = 7 × 1 = 7
Question : 3
A tap is dripping at a constant rate into a container. The level (L cm) of the water in the container is given by the equation L = 2 - $2^t$, where t is time taken in hours. Then the level of water in the container at the start is
a) 1 cm
b) 4 cm
c) 2 cm
d) 0 cm
Answer »Answer:(a)
L = 2 - $2^t$
At the start, t = 0
L = 2 - 2° = 2 - 1 = 1 cm
Question : 4
If $x = 3^{1/3} - 3^{-1/3}$, then $(3x^3 + 9x)$ is equal to
a) 6
b) 8
c) 7
d) 5
Answer »Answer:(b)
$x = 3^{1/3}- 3^{-1/3}$
On cubing both sides,
$x^3 = ((3)^{1/3})^3 -((3)^{-1/3})^3 -3×3^{1/3}×3^{-1/3}(3^{1/3}- 3^{-1/3})$
$x^3 = 3 - 3^{ - 1}$ - 3x
$x^3 + 3x = 3 - 1/3$
$x^3 + 3x = {9 -1}/3 = 8/3$
$3x^3$ + 9x = 8
Question : 5
$4^61 + 4^62 + 4^63 + 4^64$ is divisible by
a) 3
b) 13
c) 11
d) 17
Answer »Answer:(d)
$4^61 + 4^62 + 4^63 + 4^64$
= $4^61 (1 + 4 + 4^2 + 4^3)$
= $4^61(1 + 4 + 16 + 64)$
= $4^61$ × 85 which is divisible by 17.
Question : 6
If a = 7 - $4√3$, the value of $a^{1/2}+ a^{-1/2}$ is
a) 4
b) $2√3$
c) 7
d) $3√3$
Answer »Answer:(a)
a = 7 - $4√3$
$1/a=1/{7-4√3}$
=$1/{7-4√3}×{7+4√3}/{7+4√3}=7+4√3$
$(√a+1/√a)^2=a+1/a+2$
$=7-4√3+7+4√3+2=16$
$√a+1/√a=4$
GET power, indices and surds PRACTICE TEST EXERCISES
model 1 find largest and smallest value
model 2 based on simplification
model 3 based on positive and negative exponent
model 4 simplifying roots with values
model 5 simplifying roots of roots
power, indices and surds Shortcuts and Techniques with Examples
-
model 1 find largest and smallest value
Defination & Shortcuts … -
model 2 based on simplification
Defination & Shortcuts … -
model 3 based on positive and negative exponent
Defination & Shortcuts … -
model 4 simplifying roots with values
Defination & Shortcuts … -
model 5 simplifying roots of roots
Defination & Shortcuts …
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