model 6 operations of consecutive numbers (odd, even, square, etc.) Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 6 EXERCISES
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The following question based on number system topic of quantitative aptitude
(a) 5200
(b) 1000
(c) 1250
(d) 2500
The correct answers to the above question in:
Answer: (d)
S = 1 + 3 + 5 + ..... to 50 terms
Here, a = 1; d = 3 – 1 = 2; n = 50
S = $n/2[2a + (n - 1)d]$
= $50/2[2×1+ (50 - 1) ×2]$
= 25 (2 + 98) = 25 × 100 = 2500
Practice number system (model 6 operations of consecutive numbers (odd, even, square, etc.)) Online Quiz
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Read more operations on consecutive numbers Based Quantitative Aptitude Questions and Answers
Question : 1
If the sum of five consecutive integers is S, then the largest of those integers in terms of S is
a) ${S + 5}/4$
b) ${S -10}/5$
c) ${S + 4}/4$
d) ${S +10}/5$
Answer »Answer: (d)
Sum of five consecutive integers = S
Third integer = $S/5$
Largest integer = $S/5$ + 2 = ${S+10}/5$
Question : 2
The sum of three consecutive odd natural numbers each divisible by 3 is 72. What is the largest among them?
a) 27
b) 21
c) 24
d) 36
Answer »Answer: (a)
Let the numbers be 3x, 3x + 3 and 3x + 6
3x + 3x + 3 + 3x + 6 = 72
9x + 9 = 72
9x = 72 – 9 = 63
x =$63/9$ = 7
∴ Largest number = 3x + 6 = 3 × 7 + 6 = 27
Question : 3
The sum of all even numbers between 21 and 51 is
a) 560
b) 518
c) 540
d) 596
Answer »Answer: (c)
22 + 24 + 26 + ... + 50
= 2 (11 + 12 + 13 + .... + 25)
= 2 [(1 + 2 + 3 + ... + 25) – (1 + 2 + 3 ... + 10)]
= 2$({25×26}/2 - {10×11}/2)$
= 2 (325 – 55) = 2 × 270 = 540
Method 2 :
Sum of first n even numbers = n (n + 1)
Required sum = Sum of 25 even numbers from 1 to 50 – sum of 10 even numbers from 1 to 20
= 25×26 – 10 × 11 = 650 – 110 = 540
Question : 4
The sum of all the 3-digit numbers, each of which on division by 5 leaves remainder 3, is
a) 6995
b) 180
c) 1550
d) 99090
Answer »Answer: (d)
According to the question,
First number = a = 103; Last number = l = 998
If the number of such numbers be n, then,
998 = 103 + (n – 1) × 5
(n – 1) × 5= 998 – 103 = 895
n – 1 = $895/5$ = 179
n = 180
S = $n/2(a+l)$
=$180/2$(103 +998)
= 90 × 1101 = 99090
Question : 5
Out of six consecutive natural numbers, if the sum of first three is 27, what is the sum of the other three ?
a) 25
b) 36
c) 35
d) 24
Answer »Answer: (b)
x + x + 1 + x + 2 = 27
3x + 3 = 27
3x = 24
x = 8
Three consecutive no's whose sum is 27 are 8, 9,10.
Hence, next 3 consecutive no's having 36 as sum are 11, 12 and 13
Question : 6
The sum of all natural numbers between 100 and 200, which are multiples of 3 is :
a) 4980
b) 5000
c) 4950
d) 4900
Answer »Answer: (c)
Numbers divisible by 3 and lying between 100 and 200 are : 102, 105,..... 198
Let number of terms = n
198 = 102 + (n–1) 3
n–1 = ${198 - 102}/3$ = 32
n = 33
S = $n/2$(a+l) =$33/2$(102+ 198) = 4950
GET number system PRACTICE TEST EXERCISES
model 1 basic number system
model 2 divisibility, multiples, add and subtract based number system
model 3 fraction of numbers
model 4 finding unit place of a number
model 5 smallest and largest fraction/numbers
model 6 operations of consecutive numbers (odd, even, square, etc.)
number system Shortcuts and Techniques with Examples
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model 1 basic number system
Defination & Shortcuts … -
model 2 divisibility, multiples, add and subtract based number system
Defination & Shortcuts … -
model 3 fraction of numbers
Defination & Shortcuts … -
model 4 finding unit place of a number
Defination & Shortcuts … -
model 5 smallest and largest fraction/numbers
Defination & Shortcuts … -
model 6 operations of consecutive numbers (odd, even, square, etc.)
Defination & Shortcuts …
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