type 3 money multiples in ‘n’ years Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 6 EXERCISES
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The following question based on simple interest topic of quantitative aptitude
(a) 18 years
(b) 15 years
(c) 30 years
(d) 20 years
The correct answers to the above question in:
Answer: (d)
If principal be x, interest = x
and rate = r% p.a. then
Rate = ${SI × 100}/\text"Principal × Time"$
= ${x × 100}/{x × 10}$ = 10%
Now, p = x, interest = 2x
Then, time = ${SI × 100}/\text"Principal × Rate"$
= ${2x × 100}/{x × 10}$ = 20 years
Using Rule 3,
R = ${(2 - 1)}/10$ × 100%
R = 10%
T = ${(n - 1)}/R × 100$ years
= ${3 - 1}/10 × 100$ = 20 years.
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Read more money multiples in n years Based Quantitative Aptitude Questions and Answers
Question : 1
If a sum of money at simple interest doubles in 12 years, the rate of interest per annum is
a) 7.5%
b) 16$2/3$%
c) 10%
d) 8$1/3$%
Answer »Answer: (d)
Let the principal be x.
Amount = 2x
Interest = (2x - x) = x
Rate = ${S.I. × 100}/\text"Principal × Time"$
= ${x × 100}/{x × 12} = 25/3 = 8{1}/3%$
Using Rule 3,
R = ${(2 - 1)}/12 × 100%$
R = $25/3% = 8{1}/3$%
Question : 2
A sum doubles itself in 16 years, then in how many years will it triple itself; rate of interest being simple
a) 32 years
b) 25 years
c) 64 years
d) 48 years
Answer »Answer: (a)
Case I
Principal = Rs. x
Interest = Rs. x
Rate = ${SI × 100}/\text"Principal × Time"$
= ${x × 100}/{x × 16} = 25/4%$ per annum
Case II
Interest = Rs. 2x
Time = ${SI × 100}/\text"Principal × Rate"$
= ${2x × 100 × 4}/{x × 25}$ = 32 years
Using Rule 3,
R = ${(n - 1)}/T × 100%$
= ${(2 - 1)}/16 × 100%$
= $25/4 % = 6{1}/4%$
Now, T = ${(n - 1)}/R × 100%$
= ${(3 - 1)}/{25/4} × 100$
= $800/25$ = 32 years.
Question : 3
At what rate of simple interest per annum will a sum become $7/4$ of itself in 4 years ?
a) 18$1/4$%
b) 18%
c) 18$1/2$%
d) 18$3/4$%
Answer »Answer: (d)
Let the principal be x
Principal + SI = ${7x}/4$
SI = ${7x}/4 - x = {3x}/4$
Rate = ${SI × 100}/\text"Principal × Time"$
= ${3x × 100}/{4 × x × 4} = 18{3}/4%$
Using Rule 3,
R = ${(7/4 - 1)}/4 × 100%$
= $3/16$ × 100%
= $75/4% = 18{3}/4%$
Question : 4
A sum of money becomes $41/40$ of itself in $1/4$ years at a certain rate of simple interest. The rate of interest per annum is
a) 1%
b) 10%
c) 5%
d) 2.5%
Answer »Answer: (b)
Let the principal be Re.1
S.I. = $41/40 - 1 = 1/40$
Now, rate = ${\text"Interest" ×100}/{\text"Principal × Time"}$
= ${1/40 × 100}/{1 × 1/4} = {100 × 4}/40$ = 10%
Using Rule 3,
R = ${(41/40 - 1) × 100%}/{1/4}$
= $1/40 × 4 × 100%$ = 10%
simple interest Shortcuts and Techniques with Examples
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type 1 basic simple interest using formula
Defination & Shortcuts … -
type 2 increase or decrease in interest rate
Defination & Shortcuts … -
type 3 money multiples in ‘n’ years
Defination & Shortcuts … -
type 4 difference & equality of si rate & years
Defination & Shortcuts … -
type 5 si on ‘n’ years & ‘x/y ‘of sum
Defination & Shortcuts … -
type 6 si with ratios
Defination & Shortcuts …
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