type 3 money multiples in ‘n’ years Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 6 EXERCISES
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Top 799+ Simple Interest Aptitude Questions Answers Test »
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Top 999+ Aptitude Simple Interest MCQ: SSC Practice Test »
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Top 799+ Simple Interest Question and Answer Test for SSC »
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The following question based on simple interest topic of quantitative aptitude
(a) 32 years
(b) 25 years
(c) 64 years
(d) 48 years
The correct answers to the above question in:
Answer: (a)
Case I
Principal = Rs. x
Interest = Rs. x
Rate = ${SI × 100}/\text"Principal × Time"$
= ${x × 100}/{x × 16} = 25/4%$ per annum
Case II
Interest = Rs. 2x
Time = ${SI × 100}/\text"Principal × Rate"$
= ${2x × 100 × 4}/{x × 25}$ = 32 years
Using Rule 3,
R = ${(n - 1)}/T × 100%$
= ${(2 - 1)}/16 × 100%$
= $25/4 % = 6{1}/4%$
Now, T = ${(n - 1)}/R × 100%$
= ${(3 - 1)}/{25/4} × 100$
= $800/25$ = 32 years.
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Read more money multiples in n years Based Quantitative Aptitude Questions and Answers
Question : 1
At a certain rate of simple interest, a certain sum of money becomes double of itself in 10 years. It will become treble of itself in
a) 18 years
b) 15 years
c) 30 years
d) 20 years
Answer »Answer: (d)
If principal be x, interest = x
and rate = r% p.a. then
Rate = ${SI × 100}/\text"Principal × Time"$
= ${x × 100}/{x × 10}$ = 10%
Now, p = x, interest = 2x
Then, time = ${SI × 100}/\text"Principal × Rate"$
= ${2x × 100}/{x × 10}$ = 20 years
Using Rule 3,
R = ${(2 - 1)}/10$ × 100%
R = 10%
T = ${(n - 1)}/R × 100$ years
= ${3 - 1}/10 × 100$ = 20 years.
Question : 2
If a sum of money at simple interest doubles in 12 years, the rate of interest per annum is
a) 7.5%
b) 16$2/3$%
c) 10%
d) 8$1/3$%
Answer »Answer: (d)
Let the principal be x.
Amount = 2x
Interest = (2x - x) = x
Rate = ${S.I. × 100}/\text"Principal × Time"$
= ${x × 100}/{x × 12} = 25/3 = 8{1}/3%$
Using Rule 3,
R = ${(2 - 1)}/12 × 100%$
R = $25/3% = 8{1}/3$%
Question : 3
At what rate of simple interest per annum will a sum become $7/4$ of itself in 4 years ?
a) 18$1/4$%
b) 18%
c) 18$1/2$%
d) 18$3/4$%
Answer »Answer: (d)
Let the principal be x
Principal + SI = ${7x}/4$
SI = ${7x}/4 - x = {3x}/4$
Rate = ${SI × 100}/\text"Principal × Time"$
= ${3x × 100}/{4 × x × 4} = 18{3}/4%$
Using Rule 3,
R = ${(7/4 - 1)}/4 × 100%$
= $3/16$ × 100%
= $75/4% = 18{3}/4%$
Question : 4
A sum of money becomes $41/40$ of itself in $1/4$ years at a certain rate of simple interest. The rate of interest per annum is
a) 1%
b) 10%
c) 5%
d) 2.5%
Answer »Answer: (b)
Let the principal be Re.1
S.I. = $41/40 - 1 = 1/40$
Now, rate = ${\text"Interest" ×100}/{\text"Principal × Time"}$
= ${1/40 × 100}/{1 × 1/4} = {100 × 4}/40$ = 10%
Using Rule 3,
R = ${(41/40 - 1) × 100%}/{1/4}$
= $1/40 × 4 × 100%$ = 10%
Question : 5
Rs.6,000 becomes Rs.7,200 in 4 years at a certain rate of simple interest. If the rate becomes 1.5 times of itself, the amount of the same principal in 5 years will be
a) Rs.8,250
b) Rs.8,000
c) Rs.9,000
d) Rs.9,250
Answer »Answer: (a)
Using Rule 1,
SI = Rs.(7200–6000) = Rs.1200
SI = $\text"PRT"/100$
1200 = ${6000 × R × 4}/100$
R = ${1200 × 100}/{6000 × 4}$ = 5%
New rate of R = 5×1.5 = 7.5%
Then, SI = ${6000 × 7.5 × 5}/100$ = Rs.2250
Amount = Rs.(6000 + 2250) = Rs.8250
simple interest Shortcuts and Techniques with Examples
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type 1 basic simple interest using formula
Defination & Shortcuts … -
type 2 increase or decrease in interest rate
Defination & Shortcuts … -
type 3 money multiples in ‘n’ years
Defination & Shortcuts … -
type 4 difference & equality of si rate & years
Defination & Shortcuts … -
type 5 si on ‘n’ years & ‘x/y ‘of sum
Defination & Shortcuts … -
type 6 si with ratios
Defination & Shortcuts …
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