type 3 money multiples in ‘n’ years Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 6 EXERCISES
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Top 799+ Simple Interest Aptitude Questions Answers Test »
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Top 999+ Aptitude Simple Interest MCQ: SSC Practice Test »
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Top 799+ Simple Interest Question and Answer Test for SSC »
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The following question based on simple interest topic of quantitative aptitude
(a) 12$1/2$ years
(b) 16 years
(c) 10$2/3$ years
(d) 8 years
The correct answers to the above question in:
Answer: (b)
According to the question,
If principal be Rs. x, then
S.I. = Rs. x
Time = ${SI × 100}/\text"Principal × Rate"$
= ${x × 100}/{x × 25/4} = 400/25$ = 16 years
Using Rule 3,
T = ${(n - 1)}/R × 100%$
= ${2 - 1}/{25/4} × 100$
= $400/25$ = 16 years.
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Read more money multiples in n years Based Quantitative Aptitude Questions and Answers
Question : 1
A sum amounts to double in 8 years by simple interest. Then the rate of simple interest per annum is
a) 12.5%
b) 10%
c) 20%
d) 15%
Answer »Answer: (a)
Principal = Rs.x
Amount = Rs.2x
Interest = 2x - x = Rs.x
Rate = ${SI × 100}/\text"Principal × Time"$
= ${x × 100}/{x × 8} = 25/2$ = 12.5 % per annum
Using Rule 3,
R % = ${(n - 1)}/T × 100%$
= ${(2 - 1)}/8 × 100%$ = 12.5%
Question : 2
If a sum of money doubles itself in 8 years, then the interest rate in percentage is
a) 10%
b) 8$1/2$%
c) 12$1/2$%
d) 10$1/2$%
Answer »Answer: (c)
Let principal be Rs. x.
Amount = Rs.2x
Interest = Rs.(2x - x) = Rs.x
Rate = ${S.I. × 100}/\text"Principal × Time"$
= ${x × 100}/{x × 8} = 25/2$
= 12$1/2%$ per annum
Question : 3
A sum of money at simple interest trebles itself in 15 years. It will become 5 times of itself in
a) 36 years
b) 40 years
c) 25 years
d) 30 years
Answer »Answer: (d)
Let the principal be x.
Case-I
$2x = {x × R × 15}/100$
R = ${2 × 100}/15 = 40/3%$
Case-II
SI = 4x
$4x = {x × 40 × T}/300$
T = ${4 × 300}/40 = 30$ years
Using Rule 3,
R = ${(3 - 1)}/15 × 100%$
= $2/15 × 100%$
= $2/3 × 20% = 40/3%$
T = ${(n - 1)}/R$ Years
= ${(5 - 1)}/{40/3} × 100$ = 30 years.
Question : 4
In how many years will a sum of money double itself at 6$1/4$% simple interest per annum ?
a) 20 years
b) 24 years
c) 12 years
d) 16 years
Answer »Answer: (d)
TIme = ${SI × 100}/\text"Principal × Rate"$
= ${x × 100}/{x × 25/4}$ = 16 years
Using Rule 3,
T = ${(n - 1)}/{R%} years$
= ${(2 - 1)}/{25/4} × 100$ years = 16 years.
Question : 5
At what rate per cent per annum will the simple interest on a sum of money be $2/5$ of the amount in 10 years ?
a) 6%
b) 4%
c) 6$2/3$%
d) 5$2/3$%
Answer »Answer: (c)
Using Rule 1Simple Interest (S.I.)= ${\text"Principal × Rate × Time"/100$ orS.I. = ${\text"P × R × T"/100$P = ${\text"S.I." × 100}/\text"R × T"$, R = ${\text"S.I." × 100}/\text"P × T"$, T = ${\text"S.I." × 100}/\text"P × R"$ A = P + S.I. or S.I. = A - P
Let P be the principal and R% rate of interest.
S.I. = ${\text"PR" × 10}/100 = \text"PR"/10$
According to the question,
${PR}/10 = (P + {PR}/10) × 2/5$
$R/10 = (1 + R/10) × 2/5$
$R/10 = 2/5 + R/25$
$R/10 - R/25 = 2/5$
${5R - 2R}/50 = 2/5$
${3R}/50 = 2/5$
R = ${50 × 2}/{3 × 5} = 20/3 = 6{2}/3$%
Question : 6
In how many years will a sum of money double itself at 12% per annum?
a) 6 yrs. 9 months
b) 8 yrs. 6 months
c) 7 yrs. 6 months
d) 8 yrs. 4 months
Answer »Answer: (d)
If the principal be Rs.100 then S.I. = Rs.100.
Time = ${SI × 100}/\text"Principal × Rate"$
= ${100 × 100}/{100 × 12} = 25/3$ years
= 8 years 4 months
Using Rule 3,
T = ${(n - 1)}/R × 100%$
= ${(2 - 1)}/12 × 100%$
= $100/12 = 25/3$ years.
= 8$1/3$ years
= 8 years, 4 months.
simple interest Shortcuts and Techniques with Examples
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type 1 basic simple interest using formula
Defination & Shortcuts … -
type 2 increase or decrease in interest rate
Defination & Shortcuts … -
type 3 money multiples in ‘n’ years
Defination & Shortcuts … -
type 4 difference & equality of si rate & years
Defination & Shortcuts … -
type 5 si on ‘n’ years & ‘x/y ‘of sum
Defination & Shortcuts … -
type 6 si with ratios
Defination & Shortcuts …
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