Mensuration Model Questions Set 2 Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 2 EXERCISES

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The following question based on Mensuration topic of quantitative aptitude

Questions : A large water tank has the shape of a cube. If 128 $m^3$ of water is pumped out, the water level goes down by 2 m. Then the maximum capacity of the tank is

(a) 324 $m^3$

(b) 512 $m^3$

(c) 480 $m^3$

(d) 256 $m^3$

The correct answers to the above question in:

Answer: (b)

Let side of cubical water tank be 'x' meter.

Capacity of tank = $x^3$

According to question

⇒ $x^3 – 128 = (x – 2).x^2$

⇒ $x^3 – 128 = x^3 – 2x^2$

⇒ $2x^2$ = 128

⇒ $x^2$ = 64

⇒ x = 8 metre

Capacity of tank $(8)^3 = 512 m^3$

So, option (b) is correct.

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Read more model questions set 2 Based Quantitative Aptitude Questions and Answers

Question : 1

Consider the following statements : Two triangles are said to be congruent, if

  1. Three angles of one triangle are equal to the corresponding three angles of the other triangle.
  2. Three sides of one triangle are equal to the corresponding three sides of the other triangle.
  3. Two sides and the included angle of one triangle are equal to the corresponding two sides and the included angle of the other triangle.
  4. Two angles and the included side of one triangle are equal to the corresponding two angles and the included side of the other triangle.
Which of the above statements are correct?

a) 1, 2 and 4

b) 1, 2 and 3

c) 1, 3 and 4

d) 2, 3 and 4

Answer: (d)

Question : 2

In the figure given below, ABC is a triangle. BC is parallel to AE. If BC = AC, then what is the value of ∠CAE?

mensuration area and volume aptitude mcq 21 38

a) 40°

b) 20°

c) 30°

d) 50°

Answer: (d)

Given that, BC || AE

∠CBA + ∠EAB = 180°

⇒ ∠EAB =180° – 65° = 115°

∵ BC= AC

Hence, ΔABC is an isosceles triangle

mensuration-area-and-volume-aptitude-mcq

∠CBA= ∠CAB = 65°

Now, ∠EAB = ∠EAC + ∠CAB

⇒ 115° = x + 65° ⇒ x = 50°

Question : 3

ABCD is a quadrilateral such that BC = BA and CD > AD. Which one of the following is correct?

a) ∠BAD > ∠BCD

b) ∠BAD = ∠BCD

c) ∠BAD < ∠BCD

d) None of these

Answer: (a)

Construction : In quadrilateral ABCD, form A to C.

Now, in ΔABC

mensuration-area-and-volume-aptitude-mcq

∵ AB = BC ...(Given)

∴ ∠BAC = ∠BCA

(angles opposite to equal side)

In ΔADC,

∵ CD > AD

∴ ∠DAC> ∠DCA

(since in a triangle, angle opposite to greater side is bigger than the angle opposite to smaller side)

On adding eqs. (i) and (ii), we get

∠BAD > ∠BCD

Question : 4

The length of a minute hand of a wall clock is 9 cm. What is the area swept (in $cm^2$) by the minute hand in 20 min? (take π = 3.14)

a) 67.74

b) 88.78

c) 84.78

d) 57.78

Answer: (c)

The angle made by the minute hand in 20 min = 120°

∴ The area swept by the minute hand in 20 min

= $θ/{360°} × π r^2 = ∼ {120°}/{360°} × 3.14 × 9 × 9 = 84.78 cm^2$

Question : 5

In the figure given below, SPT is a tangent to the circle at P and O is the centre of the circle. If ∠QPT = α, then what is ∠POQ equal to?

mensuration area and volume aptitude mcq 24 112

a) 90° – α

b) α

c) 2α

d) 180° – 2α

Answer: (c)

Question : 6

Let the incircle to a ΔABC touch BC, AC and AB respectively at the points X, Y and Z.

  • Statement I
  • If AB > BC, then AB + AZ < BC + XC
  • Statement II
  • AZ = AY
Which one of the following is correct in respect of the above statements ?

a) Statement I is correct and Statement II is incorrect

b) Statement I and II are correct and Statements II is the correct explanation of Statement I

c) Statement I and II are correct and Statement II is not the correct explanation of Statement I

d) Statement I is incorrect and Statement II is correct

Answer: (d)

In ΔAOZ and ΔAOY,

AO = OA [common]

∠OAZ = ∠OAY [Since, OA bisect ∠A]

and ∠AZO = ∠AYO [each 90°]

∴ ΔAZO ≅ ΔAYO

mensuration-area-and-volume-aptitude-mcq

So, AZ = AY [by CPCT]

Similarly, CX = CY and BX = BZ

Now, AB > BC

∴ AZ + ZB > BX + XC

AZ > XC [∵ BX = ZB]

If AB > BC, then AB + AZ > BC + XC

So, Statement I is incorrect and Statement II is correct.

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