Mensuration Model Questions Set 2 Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 2 EXERCISES

Top 10,000+ Aptitude Memory Based Exercises

The following question based on Mensuration topic of quantitative aptitude

Questions : In the figure given below, SPT is a tangent to the circle at P and O is the centre of the circle. If ∠QPT = α, then what is ∠POQ equal to?
mensuration area and volume aptitude mcq 24 112

(a) 90° – α

(b) α

(c) 2α

(d) 180° – 2α

The correct answers to the above question in:

Answer: (c)

Practice Mensuration (Mensuration Model Questions Set 2) Online Quiz

Discuss Form

Valid first name is required.
Please enter a valid email address.
Your genuine comment will be useful for all users! Each and every comment will be uploaded to the question after approval.

Read more model questions set 2 Based Quantitative Aptitude Questions and Answers

Question : 1

The length of a minute hand of a wall clock is 9 cm. What is the area swept (in $cm^2$) by the minute hand in 20 min? (take π = 3.14)

a) 67.74

b) 88.78

c) 84.78

d) 57.78

Answer: (c)

The angle made by the minute hand in 20 min = 120°

∴ The area swept by the minute hand in 20 min

= $θ/{360°} × π r^2 = ∼ {120°}/{360°} × 3.14 × 9 × 9 = 84.78 cm^2$

Question : 2

A large water tank has the shape of a cube. If 128 $m^3$ of water is pumped out, the water level goes down by 2 m. Then the maximum capacity of the tank is

a) 324 $m^3$

b) 512 $m^3$

c) 480 $m^3$

d) 256 $m^3$

Answer: (b)

Let side of cubical water tank be 'x' meter.

Capacity of tank = $x^3$

According to question

⇒ $x^3 – 128 = (x – 2).x^2$

⇒ $x^3 – 128 = x^3 – 2x^2$

⇒ $2x^2$ = 128

⇒ $x^2$ = 64

⇒ x = 8 metre

Capacity of tank $(8)^3 = 512 m^3$

So, option (b) is correct.

Question : 3

Consider the following statements : Two triangles are said to be congruent, if

  1. Three angles of one triangle are equal to the corresponding three angles of the other triangle.
  2. Three sides of one triangle are equal to the corresponding three sides of the other triangle.
  3. Two sides and the included angle of one triangle are equal to the corresponding two sides and the included angle of the other triangle.
  4. Two angles and the included side of one triangle are equal to the corresponding two angles and the included side of the other triangle.
Which of the above statements are correct?

a) 1, 2 and 4

b) 1, 2 and 3

c) 1, 3 and 4

d) 2, 3 and 4

Answer: (d)

Question : 4

Let the incircle to a ΔABC touch BC, AC and AB respectively at the points X, Y and Z.

  • Statement I
  • If AB > BC, then AB + AZ < BC + XC
  • Statement II
  • AZ = AY
Which one of the following is correct in respect of the above statements ?

a) Statement I is correct and Statement II is incorrect

b) Statement I and II are correct and Statements II is the correct explanation of Statement I

c) Statement I and II are correct and Statement II is not the correct explanation of Statement I

d) Statement I is incorrect and Statement II is correct

Answer: (d)

In ΔAOZ and ΔAOY,

AO = OA [common]

∠OAZ = ∠OAY [Since, OA bisect ∠A]

and ∠AZO = ∠AYO [each 90°]

∴ ΔAZO ≅ ΔAYO

mensuration-area-and-volume-aptitude-mcq

So, AZ = AY [by CPCT]

Similarly, CX = CY and BX = BZ

Now, AB > BC

∴ AZ + ZB > BX + XC

AZ > XC [∵ BX = ZB]

If AB > BC, then AB + AZ > BC + XC

So, Statement I is incorrect and Statement II is correct.

Question : 5

In the figure given below, what is ∠BCD equal to?

mensuration area and volume aptitude mcq 24 122

a) 80°

b) 70°

c) 75°

d) 90°

Answer: (a)

∠BAC = ∠BDC {Angle made by same chord BC in the same side}

Now, from ΔBCD, sum of angles = 180°

∠CBD + ∠BDC + ∠BCD = 180°

∴ ∠BCD = 180° – 100° = 80°

Question : 6

A hollow right circular cylindrical vessel of volume V whose diameter is equal to its height, is completely filled with water. A heavy sphere of maximum possible volume is then completely immersed in the vessel. What volume of water remains in the vessel ?

a) ${2V}/3$

b) $V/2$

c) $V/3$

d) $V/4$

Answer: (a)

As per the given condition, the radius of sphere and cylinder will be same.

Volume of cylinder = $πR^2H = πR^2 .D = 2πR^3$

(where R = Radius)

Volume of sphere $V_s = 4/3 π R^3$

⇒ = ${V_S}/V ={4/3 π R^3}/{2π R^3} = 2/3 ⇒ V_s = 2/3 V$

Recently Added Subject & Categories For All Competitive Exams

100+ Quadratic Equation Questions Answers PDF for Bank

Quadratic Equation multiple choice questions with detailed answers for IBPS RRB SO. more than 250 Attitude practice test exercises for all competitive exams

03-Jul-2024 by Careericons

Continue Reading »

IBPS Aptitude Linear Equations MCQ Questions Answers PDF

Linear equations multiple choice questions with detailed answers for IBPS RRB SO. more than 250 Attitude practice test exercises for all competitive exams

03-Jul-2024 by Careericons

Continue Reading »

New 100+ Compound Interest MCQ with Answers PDF for IBPS

Compound Interest verbal ability questions and answers solutions with PDF for IBPS RRB PO. Aptitude Objective MCQ Practice Exercises all competitive exams

02-Jul-2024 by Careericons

Continue Reading »

100+ Mixture and Alligation MCQ Questions PDF for IBPS

Most importantly Mixture and Alligation multiple choice questions and answers with PDF for IBPS RRB PO. Aptitude MCQ Practice Exercises all Bank Exams

02-Jul-2024 by Careericons

Continue Reading »