Trigonometric Ratios & Identity Model Questions Set 1 Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on Trigonometric Ratios & Identities topic of quantitative aptitude

Questions : If sec x cosec x = 2, then what is $tan^n x + cot^n$ x equal to?

(a) $2^{n + 1}$

(b) 2

(c) 2n

(d) $2^{n – 1}$

The correct answers to the above question in:

Answer: (b)

sec x cosec x = 2

This value is possible is x = 45°

$tan^n x + cot^n x = (\text"tan x")^n + (\text"cot x")^n$

= $(tan 45°)^n + (cot 45°)^n = (1)^n + (1)^n = 2$

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Read more model questions set 1 Based Quantitative Aptitude Questions and Answers

Question : 1

If α is the angle of first quadrant such that $cosec^4 α = 17 + cot^4$ α, then what is the value of sin α?

a) $1/4$

b) $1/3$

c) $1/9$

d) $1/{16}$

Answer: (b)

$cosec^4 α - cot^4$ α = 17 (Given)

⇒ $(cosec^2 α - cot^2 α) (cosec^2 α + cot^2 α)$ = 17

⇒ 1.$({1 + cos^2 α}/{sin^2 α})$ = 17

⇒ 2 - $sin^2 α = 17 sin^2 α$

⇒ $18 sin^2 α = 2 ⇒ sin^2 α = 1/9$

∴ sin α = $1/3$ (since, α lie in first quadrant)

Question : 2

If p = $√{{1 - \text"sin x"}/{1 + \text"sin x"}}, q = {1 - \text"sin x"}/{\text"cos x"}, r = {\text"cos x"}/{1 + \text"sin x"}$
then which of the following is/are correct ?
1. p = q = r
2. $p^2$ = qr
Select the correct answer using the code given below.

a) 2 only

b) 1 only

c) Both 1 and 2

d) Neither 1 nor 2

Answer: (c)

Statement 1

1 = ${√{\text"1 - sin n"}}/{√{\text"1 + sin x"}} = √{{(\text"1 - sin x")(\text"1 - sin x")}/{(\text"1 - sin x")(\text"1 + sin x")}}$

= ${\text"1 - sin x"}/{√{1 - sin^2 x}} = {\text"1 - sin x"}/{√{cos^2 x}} = {\text"1 - sin x"}/{\text"cos x"}$

P = q

r = ${\text"cos x"}/{\text"1 + sin x"} = {\text"cos x" (\text"1 - sin x")}/{(\text"1 + sin x")(\text"1 - sin x")} = {\text"cos x" (\text"1 - sin x")}/{1 - sin^2 x}$

= ${\text"cos x" (\text"1 - sin x")}/{cos^2 x} = {\text"1 - sin x"}/{\text"cos x"}$

P = q = r

Now,

Statement 2

$p^2$ = qr

= ${\text"1 - sin x"}/{\text"cos x"} . {\text"cos x"}/{\text"1 + sin x"} = {\text"1 - sin x"}/{\text"1 + sin x"} = P^2$

So, Both are correct.

Question : 3

What is ${\text"sec x"}/{\text"cot x + tan x"}$ equal to ?

a) cos x

b) sin x

c) tan x

d) cot x

Answer: (b)

${\text"sec x"}/{\text"cot x + tan x"}$

⇒ ${1/{\text"cos x"}}/{{\text"cos x"}/{\text"sin x"} + {\text"sin x"}/{\text"cos x"}}$

⇒ ${1/{\text"cos x"}}/{{cos^2 x + sin^2 x}/{\text"sin x cos x"}}$

⇒ $1/{(\text"cos x")}$ × cos x × sin x

⇒ sin x

Question : 4

If tan θ + sec θ = 2, then tan θ is equal to

a) $5/4$

b) $3/4$

c) $3/2$

d) $5/2$

Answer: (b)

tan θ + sec θ = 2 ......(i)

As we know

⇒ $sec^2 θ - tan^2 θ$ = 1

⇒ (sec θ - tan θ)(sec θ + tan θ) = 1

⇒ sec θ - tan θ = $1/2$ ....(ii)

equation (i) - eq (ii)-

2 tan θ = 2 - 1/2

2 tan θ = $3/2 ⇒ tan θ = 3/4$

So, option (b) is correct.

Question : 5

If the given figure, BC = 15 cm and sin B = $4/5$. What is the value of AB?

a) 20 cm

b) 25 cm

c) 5 cm

d) 4 cm

Answer: (b)

BC = 15 cm and sin B = $4/5$

sin B = ${AC}/{AB} = 4/5$

trigonometric-ratios-and-identities-aptitude-mcq

then BC = 3m

But, BC = 15 (given)

then AC = 4 × 5 = 20

AB = 5 × 5 = 25.

Hence, the value of AB is 25 cm.

Question : 6

The value of cos 25° – sin 25° is

a) positive but greater than 1

b) positive but less than 1

c) negative

d) 0

Answer: (b)

Since, value of cos θ decreases, from 0° to 90° and at 45°, it is equal to the value of sin θ.

Similarly, value of sin θ increases from 0° to 90° and at 45°, it is equal to the value of cos θ

For 0° < 45°, cos θ > sin θ

So, value of cos 25° is always positive but less than 1.

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Trigonometric Ratios & Identity Model Questions Set 1

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