Set Theory Model Questions Set 2 Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 2 EXERCISES

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The following question based on Set Theory topic of quantitative aptitude

Questions : If a set A contains 60 elements and another set B contains 70 elements and there are 50 elements in common, then how many elements does A ∪ B contain?

(a) 80

(b) 100

(c) 130

(d) 70

The correct answers to the above question in:

Answer: (a)

Here, n(A) = 60, n(B) = 70, n(A ∩ B) = 50 and n(A ∪ B) = ?

We know that:

n(A ∪ B) = n(A) + n(B) – n(A ∩ B)

= 60 + 70 – 50 = 130 – 50 = 80

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Read more model question set 2 Based Quantitative Aptitude Questions and Answers

Question : 1

Which one of the following is a null set?

a) C = {Φ}

b) B = {x : x + 3 = 3}

c) A = {x is a real number : x > 1 and x < 1}

d) D = {x is a real number : x ≥ 1 and x ≤ 1}

Answer: (c)

From option (a),

A = {x is a real number : x > 1 and x < 1}.

So, there is no element which is greater or less than 1.

So, A is a null set.

From option (b),

B = {x : x + 3 = 3} = {0}

= Singleton set

From option (c):

C = {Φ} = Singleton set

From option (d),

D = {x is a real number : x ≥ 1 and x ≤ 1}

= {1} = Singleton set

Question : 2

In an examination, 35% students failed in Hindi, 45% students failed in English and 20% students failed in both the subjects. What is the percentage of students passing in both the subjects?

a) 30

b) 20

c) 0

d) 40

Answer: (d)

Let the total number of students be 100%

Number of students failed in Hindi = 35%

Number of students failed in English = 45%

Number of students failed in both the subjects = 20%

Total number of students failed = (35 + 45 – 20)% = 60%

Number of students passing in both the subjects = (100 – 60)% = 40%

Question : 3

Let A = {7, 8, 9, 10, 11, 12} and B = {7, 10, 14, 15}. What is the number of elements in (A–B) and (B–A) respectively ?

a) 2 and 2

b) 4 and 2

c) 2 and 4

d) 4 and 4

Answer: (b)

A = {7, 8, 9, 10, 11, 12}; B = {7, 10, 14, 15}

(A – B) = {8, 9, 11, 12} (B – A) = {14, 15}

n (A – B) = 4; n (B – A) = 2

Question : 4

If A and B are any two non-empty subsets of a set E, then what is A ∪ (A ∩ B) equal to?

a) A

b) A ∪ B

c) A ∩ B

d) B

Answer: (a)

A and B are non-empty subsets of E.

set-theory-aptitude-mcq

∴ A ∪ (A ∩ B) = A ∪ (Shaded portion) = A

Question : 5

If two sets A and B have 2n and 4n elements, respectively. When n is a natural number. What can be the minimum number of elements in A ∪ B?

a) 4n

b) 3n

c) 2n

d) 6n

Answer: (a)

Here, n(A ∩ B) = 2n

∴ n(A ∪ B) = n(A) + n(B) – n(A ∩ B)

= 2n + 4n – 2n = 4n

Hence, minimum number of elements of A ∪ B is 4n.

Question : 6

Let S be a set of first ten natural numbers. What is the possible number of pairs (a, b) where a, b E S and a ≠ b such that the product ab (> 12) leaves remainder 4 when divided by 12 ?

a) 8

b) 6

c) 4

d) 10

Answer: (a)

Since numbers which and leave 4 as Remainder when devided by 12 are

16, 28, 40, 52, 64, 76, 88, 100 and 124

16 = 2 × 8, 8 × 2

28 = 4 × 7, 7 × 4

40 = 4 × 10, 10 × 4, 5 × 5, 8 × 5

All remaining numbers doesn't meet the requirement

Answer is 8.

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