type 2 increase or decrease in interest rate Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on simple interest topic of quantitative aptitude

Questions : Rs.800 amounts to Rs.920 in 3 years at simple interest. If the interest rate is increased by 3%, it would amount to

(a) Rs.1,112

(b) Rs.1,056

(c) Rs.992

(d) Rs.1,182

The correct answers to the above question in:

Answer: (c)

Using Rule 1,

S.I. = Rs.(920 - 800) = Rs.120

Rate = ${\text"S.I." × 100}/\text" Principal × Time"$

= ${120 × 100}/{800 × 3}$ = 5% per annum

New rate = 8% per annum

S.I. = ${800 × 3 × 8}/100$ = Rs.192

Amount = (800 + 192) = Rs.992

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Read more increase or decrease in interest rate Based Quantitative Aptitude Questions and Answers

Question : 1

If the annual rate of simple interest increases from 10% to 12$1/2$% , a man's yearly income increases by Rs.1250. His principal (in rupees) is

a) 45,000

b) 50,000

c) 65,000

d) 60,000

Answer: (b)

Using Rule 1,

Change in SI

= $(25/2 - 10)% = 5/2%$

$5/2$% of principal = Rs.1250

Principal = Rs.${1250 × 2 × 100}/5$ = Rs.50000

Question : 2

A sum of Rs. 800 amounts to Rs.920 in 3 years at the simple interest rate. If the rate is increased by 3% p.a., what will be the sum amount to in the same period ?

a) Rs.962

b) Rs.992

c) Rs.982

d) Rs.942

Answer: (b)

Using Rule 1,

Case I,

S.I. = 920 - 800 = Rs.120

Rate = ${\text"S.I." × 100}/\text" Principal × Time"$

= ${120 × 100}/{800 × 3}$ = 5% per annum

Case II,

Rate = 8% per annum

S.I. = ${800 × 8 × 3}/100$ = Rs.192

Amount = Principal + S.I.

= (800 + 192) = Rs.992

Question : 3

A sum was invested on simple interest at a certain rate for 2 years. Had it been put at 3% higher rate, it would have fetched Rs.72 more. The sum is

a) Rs.1,500

b) Rs.1,200

c) Rs.1,800

d) Rs.1,600

Answer: (b)

Let the sum = P and original rate = R% per annum.

Then, ${P × (R + 3) × 2}/100 - {P × R × 2}/100 = 72$

${P × 3 × 2}/100 = 72$

P = ${72 × 100}/{3 × 2}$ = Rs.1200

Using Rule 13
The difference between the S.I. for a certain sum $P_1$ deposited for time $T_1$ at $R_1$ rate of interest and another sum $P_2$ deposited for time $T_2$ at $R_2$ rate of interest is
S.I. = ${P_2R_2T_2 - P_1R_1T_1}/100$

$P_1 = P, R_1 = R, T_1$ = 2

$P_2 = P, R_2 = R + 3, T_2$ = 2

S.I.= 72

72 = ${P × (R + 3) × 2 - P × R × 2}/100$

7200 = 6P

P = Rs.1200

Question : 4

The amount Rs.2,100 became Rs.2,352 in 2 years at simple interest. If the interest rate is decreased by 1%, what is the new interest ?

a) Rs.220

b) Rs.210

c) Rs.252

d) Rs.242

Answer: (b)

Using Rule 1,

S.I. = 2352 - 2100 = Rs.252

Rate = ${\text"S.I." × 100}/\text" Principal × Time"$

= ${252 × 100}/{2100 × 2}$ = 6% per annum

New rate = 5%

S.I. = ${252 × 5}/6$ = Rs.210

Question : 5

A sum of money was lent at simple interest at a certain rate for 3 years. Had it been lent at 2.5% per annum higher rate, it would have fetched Rs.540 more. The money lent was :

a) Rs.6472

b) Rs.6400

c) Rs.7200

d) Rs.6840

Answer: (c)

If the sum lent be Rs. x, then

${x × 2.5 × 3}/100 = 540$

$x = {540 × 100}/{2.5 × 3}$ = Rs.7200

Using Rule 13,

$P_1 = P, R_1 = R, T_1$ = 3

$P_2 = P, R_2 = R + 2.5%, T_2$ = 3

S.I. = Rs.540

540 = ${P × (R + 2.5%) × 3 - P × R × 3}/100$

54000 = 7.5P

P = $540000/75$

P = Rs.7200

Question : 6

A sum of Rs.2,400 amounts to Rs.3,264 in 4 years at a certain rate of simple interest. If the rate of interest is increased by 1%, the same sum in the same time would amount to

a) Rs.3,312

b) Rs.3,288

c) Rs.3,360

d) Rs.3,340

Answer: (c)

Using Rule 1
Simple Interest (S.I.)= ${\text"Principal × Rate × Time"/100$ or
S.I. = ${\text"P × R × T"/100$
P = ${\text"S.I." × 100}/\text"R × T"$, R = ${\text"S.I." × 100}/\text"P × T"$, T = ${\text"S.I." × 100}/\text"P × R"$
A = P + S.I. or S.I. = A - P

S.I. = 3264 - 2400 = Rs.864

Rate = ${\text"S.I." × 100}/\text" Principal × Time"$

= ${864 × 100}/{2400 × 4}$ = 9% per annum

New rate = 10% per annum

S.I. = ${2400 × 10 × 4}/100$ = Rs.960

Amount = 2400 + 960 = Rs.3360

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