type 4 income & expenditure based ratio & proportion problems Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on ratio & proportion topic of quantitative aptitude

Questions : The ratio of the incomes of A and B as well as of B and C is 3 : 2. If one third of A’s income exceeds one fourth of C's income by Rs.1000, what is B’s income in ?

(a) 3500

(b) 4000

(c) 2500

(d) 3000

The correct answers to the above question in:

Answer: (d)

A : B = 3 : 2 = 9 : 6

B : C = 3 : 2 = 6 : 4

A : B : C = 9 : 6 : 4

${9x}/3 - {4x}/4$= 1000

3x - x = 1000

2x = 1000

x = 500

B’s income = 6x

= 6 × 500 = Rs.3000

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Read more income and expenditure based ratio and proportion Based Quantitative Aptitude Questions and Answers

Question : 1

The income of A and B are in the ratio 2 : 3 and their expenditures are in the ratio 1 : 2. If each saves Rs.24,000, find A’s income.

a) Rs.19,200

b) Rs.48,000

c) Rs.72,000

d) Rs.24,000

Answer: (b)

Let the income of A and B be Rs.2x and Rs.3x.

and their expenditures be Rs.y and Rs.2y respectively.

2x - y = 24000 ...(i)

and 3x - 2y = 24000 ...(ii)

By equation (i) × 2 - (ii),

4x - 2y - 3x + 2y = 24000

x = 24000

A’s income

= 2 × 24000 = Rs.48000

Question : 2

The ratio of income of P and Q is 3 : 4 and the ratio of their expenditures is 2 : 3. If both of them save Rs.6000, the income of P is

a) Rs.18000

b) Rs.24000

c) Rs.12000

d) Rs.20000

Answer: (a)

Let the income of P and Q be Rs.3x and Rs.4x respectively.

Again, let their expenditures be Rs.2y and Rs.3y respectively.

According to the question.

3x - 2y = 6000 ...(i)

and 4x - 3y = 6000 ...(ii)

From equations (i) and (ii)

3x - 2y = 4x - 3y

or, 4x - 3x = 3y - 2y

or, x = y

From equation (i),

3x - 2x = 6000

x = 6000

The income of P = Rs.3x

= Rs.(3 × 6000) = Rs.18000

Question : 3

Incomes of A and B are in the ratio 4 : 3 and their annual expenses in the ratio 3 : 2. If each saves Rs.60,000 at the end of the year, the annual income of A is

a) Rs.2,40,000

b) Rs.3,60,000

c) Rs.1,50,000

d) Rs.1,20,000

Answer: (a)

Let the annual income of A and B be Rs.4x and Rs.3x

and their income be Rs.3y and Rs.2y. respectively.

4x - 3y = 60000 ...(i)

and 3x - 2y = 60000 ...(ii)

Clearly, 4x - 3y = 3x - 2y

x = y

From equation (i),

x = 60000

A’s annual income = 4x

= 4 × 60000 = Rs.240000

Question : 4

The income of A, B and C are in the ratio 3 : 7 : 4 and their expenses in the ratio 4 : 3 : 5. If A saves Rs.300 out of an income of Rs.2,400, the savings of B and C are :

a) Rs.2750 and Rs.1.525

b) Rs.3725 and Rs.1.525

c) Rs.1575 and Rs.2.625

d) Rs.4025 and Rs.575

Answer: (d)

Let the income of A, B and C be Rs.3x, Rs.7x and Rs.4x respectively

and their expenses be Rs.4y, Rs.3y and Rs.5y respectively.

3x = 2400

x = 800

4y = 2400 - 300 = 2100

y = 525

B’s saving

= (7x - 3y)

= Rs.(7 × 800 - 3 × 525)

= Rs.(5600 - 1575) = Rs.4025

and C’s savings = Rs.(4x - 5y)

= Rs.(3200 - 2625) = Rs.575

Question : 5

The ratio of income of two persons is 5 : 3 and that of their expenditures is 9 : 5. If they save Rs.2600 and Rs.1800 respectively, their incomes are :

a) Rs.10000; Rs.6000

b) Rs.9000; Rs.5400

c) Rs.6000; Rs.3600

d) Rs.8000; Rs.4800

Answer: (d)

Let the income of two persons be Rs.5x and Rs.3x respectively

and their expenditures be Rs.9y and Rs.5y respectively.

As given,

5x - 9y = 2600 ...(i)

3x - 5y = 1800 ...(ii)

By 5 × (i) - 9 × (ii) we get

25x - 27x = 13000 - 16200

- 2x = - 3200

$x = 3200/2$ = 1600

First person’s income

= Rs.(1600 × 5) = Rs.8000

Second person’s income

= 3x = Rs.(1600 × 3) = Rs.4800

Question : 6

A and B have their monthly incomes in the ratio 8 : 5, while their monthly expenditures are in the ratio 5 : 3. If they have saved Rs.12,000 and Rs.10,000 monthly respectively, then the difference in their monthly incomes is

a) Rs.44,000

b) Rs.46,000

c) Rs.42,000

d) Rs.52,000

Answer: (c)

A’s monthly income = Rs.8x

A’s monthly expenditure= Rs.5y

B’s monthly income = Rs.5x

B’s monthly expenditure= Rs.3y

According to the question,

8x - 5y = 12000 ...(i)

5x - 3y = 10000 ...(ii)

By equation (i) × 3 - (ii) × 5,

24x-15y=36000
25x-15y=50000
-+-
-x=-14000

x = 14000

Difference between monthly incomes of

A and B = 8x - 5x

= Rs.3x = Rs.(3 × 14000) = Rs.42000

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