type 4 income & expenditure based ratio & proportion problems Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (d)

Let the income of A and B be Rs.5x and Rs.3x respectively.

Let the expenses of A, B and C be Rs.8y, Rs.5y and Rs.2y respectively.

Then, 2y = 2000

$y =2000/2 = 1000$

B saves = Rs.700

3x - 5y = 700

3x - 5×1000 = 700

3x = 700 +5000 = 570

$x = 5700/3 = 1900$

A’s saving = Rs.(5x - 8y)

= Rs.(5×1900 - 8×1000)

= Rs.(9500 - 8000) = Rs.1500

Answer: (c)

A’s monthly income = Rs.8x

A’s monthly expenditure= Rs.5y

B’s monthly income = Rs.5x

B’s monthly expenditure= Rs.3y

According to the question,

8x - 5y = 12000 ...(i)

5x - 3y = 10000 ...(ii)

By equation (i) × 3 - (ii) × 5,

x = 14000

Difference between monthly incomes of

A and B = 8x - 5x

= Rs.3x = Rs.(3 × 14000) = Rs.42000

Answer: (d)

Let the income of two persons be Rs.5x and Rs.3x respectively

and their expenditures be Rs.9y and Rs.5y respectively.

As given,

5x - 9y = 2600 ...(i)

3x - 5y = 1800 ...(ii)

By 5 × (i) - 9 × (ii) we get

25x - 27x = 13000 - 16200

- 2x = - 3200

$x = 3200/2$ = 1600

First person’s income

= Rs.(1600 × 5) = Rs.8000

Second person’s income

= 3x = Rs.(1600 × 3) = Rs.4800

Answer: (a)

Income of A and B

= Rs.6x and 5x

Expenses of A and B

= Rs.4y and 3y

6x - 4y = 400 ...(i)

5x - 3y = 400 ...(ii)

By equation (i)× 3 - (ii) × 4

18x - 12y - 20x + 12y

= 1200 - 1600

2x = 400 ⇒ x = 200

Total income

= 6x + 5x = 11x = Rs.2200

Answer: (a)

Let A‘s income be Rs.2x.

B’s income = Rs.(2x - 140)

C’s income = Rs.3x

D’s income = Rs.(3x - 80)

According to the question,

B : D = 1 : 2

2 (2x - 140) = 3x - 80

4x - 280 = 3x - 80

4x - 3x = 280 - 80

x = Rs. 200

A’s income

= Rs.(2 × 200) = Rs.400

B’s income

= Rs.(400 - 140) = Rs.260

C’s income

= Rs.(3 × 200) = Rs.600

D’s income

= Rs.(600 - 80) = Rs.520

Answer: (b)

Let the income of man be = Rs.11x

and his expenditure be Rs.10x.

Savings = x = Rs.9000

Monthly income of man

= ${11 × 9000}/12$ = Rs.8250