type 4 income & expenditure based ratio & proportion problems Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (a)

Let the income of two persons (A and B) be Rs.2x and Rs.3x respectively.

Again let the expenditures of A and B be Rs.5y and Rs.9y respectively.

2x - 5y = 600 ...(i)

3x - 9y = 600 ...(ii)

From equations (i) and (ii),

2x - 5y = 3x - 9y

x = 4y

From equation (i),

2 × 4y - 5y = 600

3y = 600 ⇒ y = 200

x = 4 × 200 = 800

A’s income = 2x

= 2 × 800 = Rs.1600

B’s income = 3x

= 3 × 800 = Rs.2400

Answer: (d)

Let the income of A and B be Rs.5x and Rs.3x respectively.

Let the expenses of A, B and C be Rs.8y, Rs.5y and Rs.2y respectively.

Then, 2y = 2000

$y =2000/2 = 1000$

B saves = Rs.700

3x - 5y = 700

3x - 5×1000 = 700

3x = 700 +5000 = 570

$x = 5700/3 = 1900$

A’s saving = Rs.(5x - 8y)

= Rs.(5×1900 - 8×1000)

= Rs.(9500 - 8000) = Rs.1500

Answer: (c)

A’s monthly income = Rs.8x

A’s monthly expenditure= Rs.5y

B’s monthly income = Rs.5x

B’s monthly expenditure= Rs.3y

According to the question,

8x - 5y = 12000 ...(i)

5x - 3y = 10000 ...(ii)

By equation (i) × 3 - (ii) × 5,

x = 14000

Difference between monthly incomes of

A and B = 8x - 5x

= Rs.3x = Rs.(3 × 14000) = Rs.42000

Answer: (a)

Let A‘s income be Rs.2x.

B’s income = Rs.(2x - 140)

C’s income = Rs.3x

D’s income = Rs.(3x - 80)

According to the question,

B : D = 1 : 2

2 (2x - 140) = 3x - 80

4x - 280 = 3x - 80

4x - 3x = 280 - 80

x = Rs. 200

A’s income

= Rs.(2 × 200) = Rs.400

B’s income

= Rs.(400 - 140) = Rs.260

C’s income

= Rs.(3 × 200) = Rs.600

D’s income

= Rs.(600 - 80) = Rs.520

Answer: (b)

Let the income of man be = Rs.11x

and his expenditure be Rs.10x.

Savings = x = Rs.9000

Monthly income of man

= ${11 × 9000}/12$ = Rs.8250

Answer: (c)

Let the monthly salary of A, B & C be 2x, 3x and 5x

now, 5x - 2x = 12,000

3x = 12000 or x = 4000

Monthly salary of B

= 3 × 4000 = 12,000

Annual salary of B

= 12000 × 12 = Rs.144000