model 1 Basic formula of LCM & HCF Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 5 EXERCISES
The following question based on LCM & HCF topic of quantitative aptitude
(a) 60
(b) 72
(c) 36
(d) 48
The correct answers to the above question in:
Answer: (c)
Let the numbers be 6x and 6y where x and y are prime to each other.
∴ 6x × 6y = 216
⇒ xy = $216/{6 × 6}$ = 6
∴ LCM = 6xy = 6 × 6 = 36
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Read more finding lcm Based Quantitative Aptitude Questions and Answers
Question : 1
The product of two numbers is 1280 and their H.C.F. is 8. The L.C.M. of the number will be :
a) 150
b) 160
c) 140
d) 120
Answer »Answer: (b)
Using Rule 1 :
1st number × 2nd number = L.C. M. × H.C.F,
HCF × LCM = Product of two numbers
⇒ 8 × LCM = 1280
⇒ LCM = $1280/8$ =160
Question : 2
The HCF and LCM of two numbers are 12 and 924 respectively. Then the number of such pairs is
a) 1
b) 0
c) 3
d) 2
Answer »Answer: (d)
Let the numbers be 12x and 12y where x and y are prime to each other.
∴ LCM = 12xy
∴ 12xy = 924
⇒ xy = 77
∴ Possible pairs = (1,77) and (7,11)
Question : 3
The H.C.F. and L.C.M. of two numbers are 8 and 48 respectively. If one of the number is 24, then the other number is
a) 36
b) 48
c) 16
d) 24
Answer »Answer: (c)
Using Rule 1 :
1st number × 2nd number = L.C. M. × H.C.F,
First number × second number = HCF × LCM
⇒ 24 × second number = 8 × 48
∴ Second number =${8 × 48}/24$ = 16
Question : 4
The H.C.F. of two numbers is 8. Which one of the following can never be their L.C.M.?
a) 48
b) 24
c) 60
d) 56
Answer »Answer: (c)
HCF of two numbers is 8.
This means 8 is a factor common to both the numbers. LCM is common multiple for the two numbers, it is divisible by the two numbers. So, the required answer = 60
Question : 5
The L.C.M. of three different numbers is 120. Which of the following cannot be their H.C.F.?
a) 12
b) 8
c) 35
d) 24
Answer »Answer: (c)
LCM = 2 × 2 × 2 × 3 × 5
Hence, HCF = 4, 8, 12 or 24
According to question
35 cannot be H.C.F. of 120.
Question : 6
The HCF and product of two numbers are 15 and 6300 respectively. The number of possible pairs of the numbers is
a) 3
b) 4
c) 1
d) 2
Answer »Answer: (d)
Let the number be 15x and 15y, where x and y are co –prime.
∴ 15x × 15y = 6300
⇒ xy = $6300/{15 ×15}$ = 28
So, two pairs are (7, 4) and (14, 2)
LCM & HCF Shortcuts and Techniques with Examples
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model 1 Basic formula of LCM & HCF
Defination & Shortcuts … -
model 2 find lcm of numbers
Defination & Shortcuts … -
model 3 find hcf of numbers
Defination & Shortcuts … -
model 4 addition, subtraction, multiplication and division with lcm & hcf
Defination & Shortcuts … -
model 5 lcm & hcf vs ratios
Defination & Shortcuts …
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