model 1 Basic formula of LCM & HCF Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on LCM & HCF topic of quantitative aptitude

Questions : The L.C.M. of three different numbers is 120. Which of the following cannot be their H.C.F.?

(a) 12

(b) 8

(c) 35

(d) 24

The correct answers to the above question in:

Answer: (c)

LCM = 2 × 2 × 2 × 3 × 5

Hence, HCF = 4, 8, 12 or 24

According to question

35 cannot be H.C.F. of 120.

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Read more finding lcm Based Quantitative Aptitude Questions and Answers

Question : 1

The H.C.F. of two numbers is 8. Which one of the following can never be their L.C.M.?

a) 48

b) 24

c) 60

d) 56

Answer: (c)

HCF of two numbers is 8.

This means 8 is a factor common to both the numbers. LCM is common multiple for the two numbers, it is divisible by the two numbers. So, the required answer = 60

Question : 2

The product of two numbers is 216. If the HCF is 6, then their LCM is

a) 60

b) 72

c) 36

d) 48

Answer: (c)

Let the numbers be 6x and 6y where x and y are prime to each other.

∴ 6x × 6y = 216

⇒ xy = $216/{6 × 6}$ = 6

∴ LCM = 6xy = 6 × 6 = 36

Question : 3

The product of two numbers is 1280 and their H.C.F. is 8. The L.C.M. of the number will be :

a) 150

b) 160

c) 140

d) 120

Answer: (b)

Using Rule 1 :

1st number × 2nd number = L.C. M. × H.C.F,

HCF × LCM = Product of two numbers

⇒ 8 × LCM = 1280

⇒ LCM = $1280/8$ =160

Question : 4

The HCF and product of two numbers are 15 and 6300 respectively. The number of possible pairs of the numbers is

a) 3

b) 4

c) 1

d) 2

Answer: (d)

Let the number be 15x and 15y, where x and y are co –prime.

∴ 15x × 15y = 6300

⇒ xy = $6300/{15 ×15}$ = 28

So, two pairs are (7, 4) and (14, 2)

Question : 5

The HCF and LCM of two numbers are 18 and 378 respectively. If one of the number is 54, then the other number is

a) 144

b) 126

c) 238

d) 198

Answer: (b)

Using Rule 1 :

1st number × 2nd number = L.C. M. × H.C.F,

Second number =${HCF × LCM}/{First number} $

= ${18 ×378}/54$ = 126

Question : 6

The HCF of two numbers is 16 and their LCM is 160. If one of the number is 32, then the other number is

a) 80

b) 48

c) 112

d) 96

Answer: (a)

Using Rule 1 :

1st number × 2nd number = L.C. M. × H.C.F,

We know that,

First number × Second number = LCM × HCF

⇒ Second number = ${16 × 160}/32$ = 80

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