model 2 find lcm of numbers Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 5 EXERCISES

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The following question based on LCM & HCF topic of quantitative aptitude

Questions : Three bells ring simultaneously at 11a.m. They ring at regular intervals of 20 minutes, 30 minutes, 40 minutes respectively. The time when all the three ring together next is

(a) 1.30 p.m.

(b) 1.15 p.m.

(c) 1 p.m.

(d) 2 p.m.

The correct answers to the above question in:

Answer: (c)

LCM of 20, 30 and 40 minutes = 120 minutes

Hence, the bells will toll together again after 2 hours i.e. at 1 p.m.

Practice LCM & HCF (model 2 find lcm of numbers) Online Quiz

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Read more find lcm using formula Based Quantitative Aptitude Questions and Answers

Question : 1

The number nearest to 10000, which is exactly divisible by each of 3, 4, 5, 6, 7 and 8, is :

a) 10000

b) 9996

c) 10080

d) 9240

Answer: (c)

LCM of 3, 4, 5, 6, 7, 8 = 840

11$760/840$ = 10000

Since, the remainder 760 is more than half of the divisor 840.

∴ The nearest number

= 10000 + (840 – 760) = 10080

Question : 2

A number which when divided by 10 leaves a remainder of 9, when divided by 9 leaves a remainder of 8, and when divided by 8 leaves a remainder of 7, is :

a) 1359

b) 359

c) 539

d) 1539

Answer: (b)

Using Rule 5,

Here, Divisor – remainder = 1

e.g., 10 – 9 = 1, 9 – 8 = 1, 8 – 7 = 1

∴ Required number = (L.C.M. of 10, 9, 8) –1

= 360 – 1 = 359

Question : 3

The least multiple of 7, which leaves the remainder 4, when divided by any of 6, 9, 15 and 18, is

a) 364

b) 184

c) 94

d) 76

Answer: (a)

LCM of 6, 9, 15 and 18

26,9,15,18
33,9,15,9
31,3,5,3
 1,1,5,1

∴ LCM = 2 × 3 × 3 × 5 = 90

∴ Required number = 90k + 4,

which must be a multiple of 7 for some value of k.

For k = 4,

Number = 90 × 4 + 4 = 364,

which is exactly divisible by 7.

Question : 4

The least number which when divided by 16, 18, 20 and 25 leaves 4 as remainder in each case but when divided by 7 leaves no remainder is

a) 18004

b) 18002

c) 18000

d) 17004

Answer: (a)

LCM of 16, 18, 20 and 25 = 3600

∴ Required number = 3600K + 4 which is exactly divisible by 7 for certain value of K.

When K = 5,

number = 3600 × 5 + 4

= 18004 which is exactly divisible by 7.

Question : 5

The LCM of four consecutive numbers is 60. The sum of the first two numbers is equal to the fourth number. What is the sum of four numbers?

a) 24

b) 21

c) 14

d) 17

Answer: (c)

260
230
315,
 5

∴ 60 = 2 × 2 × 3 × 5

i.e., Numbers = 2, 3, 4 and 5

∴ Required sum = 2 + 3 + 4 + 5 = 14

Question : 6

The number nearest to 43582 divisible by each of 25, 50 and 75 is :

a) 43550

b) 43600

c) 43650

d) 43500

Answer: (c)

LCM of 25, 50 and 75 = 150

On dividing 43582 by 150, remainder = 82

290$82/150$ = 43582

∴ Required number = 43582 + (150 – 82)

= 43650

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