model 2 find lcm of numbers Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 5 EXERCISES
The following question based on LCM & HCF topic of quantitative aptitude
(a) 9765
(b) 9766
(c) 9764
(d) 9763
The correct answers to the above question in:
Answer: (d)
The difference between divisor and the corresponding remainder is equal.
LCM of 3, 5, 7 and 9 = 315 Largest 4-digit number = 9999
31$234/315$ = 9999
∴ Number divisible by 315 = 9999 – 234 = 9765
Required number = 9765 – 2 = 9763
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Read more find lcm using formula Based Quantitative Aptitude Questions and Answers
Question : 1
Find the greatest number of five digits which when divided by 3, 5, 8, 12 have 2 as remainder :
a) 99962
b) 99960
c) 99958
d) 99999
Answer »Answer: (a)
Using Rule 4,
i.e. When a number is divided by x, y or z leaving same remainder ‘R’ in each case then that number must be K + R where k is LCM of x, y and z.
The greatest number of five digits is 99999.
LCM of 3, 5, 8 and 12
2 | 3, | 5, | 8, | 12 |
2 | 3, | 5, | 4, | 6 |
3 | 3, | 5, | 2, | 3 |
1, | 5, | 2, | 1 |
∴ LCM = 2 × 2 × 3 × 5 × 2 = 120 After dividing 99999 by 120, we get 39 as remainder 99999 – 39 = 99960 = (833 × 120)
99960 is the greatest five digit number divisible by the given divisors.
In order to get 2 as remainder in each case we will simply add 2 to 99960.
∴ Greatest number = 99960 + 2 = 99962
Question : 2
Three electronic devices make a beep after every 48 seconds, 72 seconds and 108 seconds respectively. They beeped together at 10 a.m. The time when they will next make a beep together at the earliest is
a) 10 : 07 : 48 hours
b) 10 : 07 : 36 hours
c) 10 : 07 : 24 hours
d) 10 : 07 : 12 hours
Answer »Answer: (d)
Required time = LCM of 48, 72 and 108 seconds
2 | 48, | 72, | 108 |
2 | 24, | 36, | 54 |
2 | 12, | 18, | 54 |
3 | 6, | 9, | 27 |
3 | 2, | 3, | 9 |
2, | 1, | 3 |
∴ LCM = 2 × 2 × 2 × 2 × 3 × 3 × 3 = 432 seconds
= 7 minutes 12 second
∴ Required time = 10 : 07 : 12 hours
Question : 3
Which is the least number which when doubled will be exactly divisible by 12, 18, 21 and 30 ?
a) 196
b) 630
c) 1260
d) 2520
Answer »Answer: (b)
The LCM of 12, 18, 21, 30
2 | 12, | 18, | 21, | 30 |
3 | 6, | 9, | 21, | 15 |
2, | 3, | 7, | 5 |
∴LCM = 2 × 3 × 2 × 3 × 7 × 5 = 1260
∴ The required number
=$1260/2$ = 630
Question : 4
If the students of a class can be grouped exactly into 6 or 8 or 10, then the minimum number of students in the class must be
a) 240
b) 180
c) 120
d) 60
Answer »Answer: (c)
Required number of students = LCM of 6, 8, 10 = 120
Question : 5
When a number is divided by 15, 20 or 35, each time the remainder is 8. Then the smallest number is
a) 338
b) 328
c) 427
d) 428
Answer »Answer: (d)
Using Rule 5,
LCM of 15, 20 and 35 = 420
∴ Required least number = 420 + 8 = 428
Question : 6
The smallest square number divisible by 10, 16 and 24 is
a) 3600
b) 2500
c) 1600
d) 900
Answer »Answer: (a)
We find LCM of = 10, 16, 24
2 | 10, | 16, | 24 |
2 | 5, | 8, | 12 |
2 | 5, | 4, | 6 |
2 | 5, | 2, | 3 |
3 | 5, | 1, | 3 |
5 | 5, | 1, | 1 |
1, | 1, | 1 |
∴ LCM = $2^2$ × $2^2$ × 3 × 5
∴ Required number
= 2 × 2 × 2 × 2 × 3 × 3 × 5 × 5
= 3600
LCM & HCF Shortcuts and Techniques with Examples
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model 1 Basic formula of LCM & HCF
Defination & Shortcuts … -
model 2 find lcm of numbers
Defination & Shortcuts … -
model 3 find hcf of numbers
Defination & Shortcuts … -
model 4 addition, subtraction, multiplication and division with lcm & hcf
Defination & Shortcuts … -
model 5 lcm & hcf vs ratios
Defination & Shortcuts …
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