model 3 find hcf of numbers Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 5 EXERCISES

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The following question based on LCM & HCF topic of quantitative aptitude

Questions : The greatest number, which when divide 989 and 1327 leave remainders 5 and 7 respectively, is :

(a) 32

(b) 16

(c) 8

(d) 24

The correct answers to the above question in:

Answer: (d)

Using Rule 7,

(The largest number which when divide the numbers a, b and c give remainders as p, q, r respectively is given by H.C.F. of (a – p), (b – q) and (c – r). )

Required number

= HCF of (989 – 5) and (1327 – 7)

= HCF of 984 and 1320 = 24

∴ HCF = 24

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Read more find hcf using formula Based Quantitative Aptitude Questions and Answers

Question : 1

Three sets of English, Mathematics and Science books containing 336, 240, 96 books respectively have to be stacked in such a way that all the books are stored subject-wise and the height of each stack is the same. Total number of stacks will be

a) 48

b) 21

c) 14

d) 22

Answer: (c)

Number of books in each stack

= HCF of 336, 240, 96 = 48

∴ Total number of stacks

=$336/48 + 240/ 48 + 96/48$

=7 + 5 + 2 = 14

Question : 2

Find the greatest number which will exactly divide 200 and 320.

a) 40

b) 20

c) 10

d) 16

Answer: (a)

Required number = HCF of 200 and 320 = 40

Illustration :

Question : 3

The greatest number that divides 411, 684, 821 and leaves 3, 4 and 5 as remainders, respectively, is

a) 204

b) 146

c) 254

d) 136

Answer: (d)

Using Rule 7,

(The largest number which when divide the numbers a, b and c give remainders as p, q, r respectively is given by H.C.F. of (a – p), (b – q) and (c – r). )

Required number

= HCF of 411 – 3 = 408; 684 – 4 = 680 and 821 – 5 = 816

HCF of 408 and 816 = 408

HCF of 408 and 680

∴ Required number = 136

Question : 4

Find the greatest number that will divide 390, 495 and 300 without leaving a remainder.

a) 35

b) 15

c) 5

d) 25

Answer: (b)

Required number = HCF of 390, 495 and 300 = 15

Illustration :

HCF of 15 and 300 = 15

Question : 5

The largest number, which divides 25, 73 and 97 to leave the same remainder in each case, is

a) 6

b) 23

c) 24

d) 21

Answer: (c)

Using Rule 7,

Let x be the remainder.

Then, (25 – x ), (73 – x ), and (97 – x )

Will be exactly divisible by the required number.

∴ Required number

= HCF of (73 –x ) – (25 –x ), (97 –x ) – (73 –x ) and (97 –x ) – (25 –x )

= HCF of (73 –25), (97 –73), and (97 –25)

= HCF of 48, 24 and 72 = 24

Question : 6

A farmer has 945 cows and 2475 sheep. He farms them into flocks, keeping cows and sheep separate and having the same number of animals in each flock. If these flocks are as large as possible, then the maximum number of animals in each flock and total number of flocks required for the purpose are respectively

a) 46 and 75

b) 9 and 380

c) 15 and 228

d) 45 and 76

Answer: (d)

First of all we find the HCF of 945 and 2475. HCF = 45

Illustration :

∴ Maximum number of animals in each flock = 45

Required total number of flocks = $945/45 + 2475/45$

= 21 + 55 = 76

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