model 3 find hcf of numbers Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 5 EXERCISES
The following question based on LCM & HCF topic of quantitative aptitude
(a) 60
(b) 30
(c) 18
(d) 45
The correct answers to the above question in:
Answer: (d)
Using Rule 7,
3026 –11 = 3015 and 5053 –13 = 5040
Required number = HCF of 3015 and 5040
∴ Required number = 45
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Read more find hcf using formula Based Quantitative Aptitude Questions and Answers
Question : 1
Two pipes of length 1.5 m and 1.2 m are to be cut into equal pieces without leaving any extra length of pipes. The greatest length of the pipe pieces of same size which can be cut from these two lengths will be
a) 0.41 metre
b) 0.4 metre
c) 0.13 metre
d) 0.3 metre
Answer »Answer: (d)
Maximum length of each piece
= HCF of 1.5 metre and 1.2 metre
= 0.3 metre
Illustration :
∴ HCF of 1.5 and 1.2 metre = 0.3 metre
Question : 2
A farmer has 945 cows and 2475 sheep. He farms them into flocks, keeping cows and sheep separate and having the same number of animals in each flock. If these flocks are as large as possible, then the maximum number of animals in each flock and total number of flocks required for the purpose are respectively
a) 46 and 75
b) 9 and 380
c) 15 and 228
d) 45 and 76
Answer »Answer: (d)
First of all we find the HCF of 945 and 2475. HCF = 45
Illustration :
∴ Maximum number of animals in each flock = 45
Required total number of flocks = $945/45 + 2475/45$
= 21 + 55 = 76
Question : 3
The largest number, which divides 25, 73 and 97 to leave the same remainder in each case, is
a) 6
b) 23
c) 24
d) 21
Answer »Answer: (c)
Using Rule 7,
Let x be the remainder.
Then, (25 – x ), (73 – x ), and (97 – x )
Will be exactly divisible by the required number.
∴ Required number
= HCF of (73 –x ) – (25 –x ), (97 –x ) – (73 –x ) and (97 –x ) – (25 –x )
= HCF of (73 –25), (97 –73), and (97 –25)
= HCF of 48, 24 and 72 = 24
Question : 4
The greatest number by which 2300 and 3500 are divided leaving the remainders of 32 and 56 respectively, is
a) 84
b) 168
c) 136
d) 42
Answer »Answer: (a)
Using Rule 7,
(The largest number which when divide the numbers a, b and c give remainders as p, q, r respectively is given by H.C.F. of (a – p), (b – q) and (c – r). )
Required number
= HCF of 2300 – 32
= 2268 and 3500 – 56 = 3444
∴ HCF = 84
Question : 5
What is the least number of square tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?
a) 814
b) 841
c) 840
d) 820
Answer »Answer: (a)
Length of the floor
= 15 m 17 cm = 1517 cm
Breadth of the floor
= 9m 2 cm = 902 cm.
Area of the floor
= 1517 × 902 $cm^2$
The number of square tiles will be least, when the size of each tile is maximum.
∴ Size of each tile = HCF of 1517 and 902 = 41
∴ Required number of tiles
=${1517× 902}/{41× 41}$ = 814
Question : 6
The greatest number, by which 1657 and 2037 are divided to give remainders 6 and 5 respectively, is
a) 305
b) 133
c) 127
d) 235
Answer »Answer: (c)
Using Rule 7,
(The largest number which when divide the numbers a, b and c give remainders as p, q, r respectively is given by H.C.F. of (a – p), (b – q) and (c – r).)
We have to find HCF of
(1657 – 6 = 1651) and (2037 – 5 = 2032)
1651 = 13 × 127
2032 = 16 × 127
∴ HCF = 127
So, required number will be 127.
LCM & HCF Shortcuts and Techniques with Examples
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model 1 Basic formula of LCM & HCF
Defination & Shortcuts … -
model 2 find lcm of numbers
Defination & Shortcuts … -
model 3 find hcf of numbers
Defination & Shortcuts … -
model 4 addition, subtraction, multiplication and division with lcm & hcf
Defination & Shortcuts … -
model 5 lcm & hcf vs ratios
Defination & Shortcuts …
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