Model 6  Efficiency of the worker Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on time & work topic of quantitative aptitude

Questions : Jyothi can do $3/4$ of a job in 12 days. Mala is twice as efficient as Jyothi. In how many days will Mala finish the job ?

(a) 16 days

(b) 6 days

(c) 8 days

(d) 12 days

The correct answers to the above question in:

Answer: (c)

Using Rule 1
If $M_1$ men can finish $W_1$ work in $D_1$ days and $M_2$ men can finish $W_2$ work in $D_2$ days then, Relation is
${M_1D_1}/{W_1} = {M_2D_2}/{W_2}$ and
If $M_1$ men finish $W_1$ work in $D_1$ days, working $T_1$ time each day and $M_2$ men finish $W_2$ work in $D_2$ days, working $T_2$ time each day, then
${M_1D_1T_1}/{W_1} = {M_2D_2T_2}/{W_2}$

Jyothi can do $3/4$ th of a job in 12 days.

Jyothi can do 1 job in ${12 × 4}/3$ = 16 days.

As Mala is twice as efficient as Jyothi,

Mala will finish the job in 8 days.

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Read more efficiency of the worker Based Quantitative Aptitude Questions and Answers

Question : 1

A does 20% less work than B. If A can complete a piece of work in 7$1/2$ hours, then B can do it in

a) 5 hours

b) 6$1/2$ hours

c) 6 hours

d) 5$1/2$ hours

Answer: (c)

A does 20% less work than B.

Ratio of time taken = 5 : 4

A completes a work in $15/2$ hours

Time taken by B to do the same work

= $15/2 × 4/5$ = 6 hours.

Question : 2

A can do a work in 5 days less than the time taken by B to do it. If both of them together take11$1/9$ days, then the time taken by ‘B’ alone to do the same work (in days) is

a) 30

b) 15

c) 20

d) 25

Answer: (d)

Using Rule 2,

If the time taken by B to complete the work be x days,

then time taken by A = (x - 5) days

$1/x + 1/{x - 5} = 9/100$

⇒ ${x - 5 + x}/{x(x - 5)} = 9/100$

⇒ $9x^2 - 45x = 200x –500$

⇒ $9x^2 - 245x + 500 = 0$

⇒ $9x^2 - 225x - 20x + 500 = 0$

⇒ $9x (x - 25) - 20 (x - 25)$ = 0

⇒ $(x - 25) (9x - 20)$ = 0

⇒ $x = 25$ because $x ≠ 20/9$

Question : 3

Shashi can do a piece of work in 20 days. Tanya is 25% more efficient than Shashi. The number of days taken by Tanya to do the same piece of work is :

a) 25

b) 15

c) 16

d) 18

Answer: (c)

Time taken by Shashi in doing 1 work = 20 days

Tanya is 25% more efficient than Shashi.

Time taken by Tanya

= $100/125 × 20$ = 16 days

Question : 4

If A, B and C can complete a work in 6 days. If A can work twice faster than B and thrice faster than C, then the number of days C alone can complete the work is :

a) 11 days

b) 33 days

c) 44 days

d) 22 days

Answer: (b)

Using Rule 3,

Let time taken by A = x days

Time taken by B = 2x days

Time taken by C = 3x days

According to the question,

$1/x + 1/{2x} + 1/{3x}$ = 1 6

${6 + 3 + 2}/{6x} = 1/6$

$11/{6x} = 1/6$

6x = 6 × 11

$x = {6 × 11}/6$ = 11

Time taken by C alone = 3x = 3 × 11 = 33 days

Question : 5

Two workers A and B working together completed a job in 5 days. If A worked twice as efficiently as he actually did and B worked $1/3$ as efficiently as he actually did, the work would have been completed in 3 days. To complete the job alone, A would require

a) 8$3/4$ days

b) 5$1/5$ days

c) 6$1/4$ days

d) 7$1/2$ days

Answer: (c)

Using Rule 2,

If A alone does the work in x days and B alone does the work in y days, then

$1/x + 1/y = 1/5$ ...(i)

Again, $2/x + 1/{3y} = 1/3$ ...(ii)

By equation (ii) × 3 - (i),

$6/x + 1/y - 1/x - 1/y = 1 - 1/5$

$6/x - 1/x = 4/5$

${6 - 1}/x = 4/5$

$x = 25/4 = 6{1}/4$ days

Question : 6

A 10 hectare field is reaped by 2 men, 3 women and 4 children together in 10 days. If working capabilities of a man, a woman and a child are in the ratio 5 : 4 : 2, then a 16 hectare field will be reaped by 6 men,4 women and 7 children in

a) 8 days

b) 5 days

c) 6 days

d) 7 days

Answer: (a)

Using Rule 1,

Ratio of the working capabilities of a man, a woman and a child = 5 : 4 : 2

Ratio of man, woman and child equivalence = $1/5 : 1/4 : 1/2$

= $1/5 × 20 : 1/4 × 20 : 1/2 × 20$ = 4 : 5 : 10

or 4 men ≡ 5 women ≡ 10 children

4 men = 10 children

2 men ≡ 5 children and 6 men ≡ 15 children

5 women = 10 children

3 women ≡ 6 children

4 women ≡ 8 children

2 men + 3 women + 4 Children = 15 children

6 men + 4 women + 7 children = 30 children

ChildrenFieldDays
151010
3016x

∴ ${30 : 15}/{10 : 16}]$ : : 10 : x

where, x is no. of days

30 × 10 × x = 15 × 16 × 10

x = ${15 × 16 × 10}/{30 × 10} = 8$ days

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