model 2 divisibility, multiples, add and subtract based number system Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 6 EXERCISES

Top 10,000+ Aptitude Memory Based Exercises

The following question based on number system topic of quantitative aptitude

Questions : A number when divided by 91 gives a remainder 17. When the same number is divided by 13, the remainder will be ?

(a) 0

(b) 4

(c) 6

(d) 3

The correct answers to the above question in:

Answer: (b)

Here, the first divisor (91) is a multiple of the second divisor (13).

∴ Required remainder = Remainder obtained on dividing 17 by 13

⇒ 17 = ( 13 × 1 ) + 4

Hence Required remainder = 4

Practice number system (model 2 divisibility, multiples, add and subtract based number system) Online Quiz

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Read more divide multiple add subtract Based Quantitative Aptitude Questions and Answers

Question : 1

Each member of a picnic party contributed twice as many rupees as the total number of members and the total collection was 3042. The number of members present in the party was ?

a) 2

b) 32

c) 40

d) 39

Answer: (d)

Let the total number of members be X.

Then, each member's contribution =Rs. 2X

Given, X × 2X = 3042

⇒ 2X= 3042

⇒ X= 1521

⇒ X = 39

Question : 2

The expression 26n – 42n, where n is a natural number is always divisible by

a) 15

b) 18

c) 36

d) 48

Answer: (d)

The expression 26n − 42n = (26)n − (42)n

= 64n − 16n

Which is divisible by 64 –16= 48

Therefore the required answer is 48.

 

Question : 3

A student was asked to divide a number by 6 and add 12 to the quotient. He, however, first added 12 to the number and then divided it by 6, getting 112 as the answer. The correct answer should have been ?

a) 124

b) 122

c) 118

d) 114

Answer: (b)

Let the number be p.

According to the question,

∴ $\text"p + 12"/6 = 112$

⇒   p + 12 = 672

⇒   p = 672 – 12 = 660

∴  Correct answer = $\text"600"/6 = 112$

 

Correct answer =  110 + 12 = 122

Question : 4

The greatest common divisor of 33333 + 1 and 33334 + 1 is ?

a) 2

b) 1

c) 33333 + 1

d) 20

Answer: (c)

Question : 5

If a and b are two odd positive integers, by which of the following integers is (a4 – b4) always divisible ?

a) 3

b) 6

c) 8

d) 12

Answer: (c)

$a^4 - b^4 = (a - b) (a + b) (a^2 + b^2)$,

Where a and b are odd positive integers.

If two positive integers are odd, then their sum, difference and sum of their squares are always even.

∴ (a - b) (a + b) and $(a^2 + b^2)$ are divisible by 2.

Hence (a - b) (a + b) x $(a^2 + b^2) = a^4 - b^4$ is always divisible by $2^3 = 8$

Question : 6

(49)15 – 1 is exactly divisible by :

a) 50

b) 51

c) 29

d) 8

Answer: (d)

As we know, xn – an is exactly divisible by (x – a) if n is odd.

∴ (49)15 – (1 )15 is exactly divisible by 49 – 1 = 48, that is a multiple of 8.

Hence required answer is 8.

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