model 2 divisibility, multiples, add and subtract based number system Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 6 EXERCISES

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The following question based on number system topic of quantitative aptitude

Questions : If a and b are two odd positive integers, by which of the following integers is (a4 – b4) always divisible ?

(a) 3

(b) 6

(c) 8

(d) 12

The correct answers to the above question in:

Answer: (c)

$a^4 - b^4 = (a - b) (a + b) (a^2 + b^2)$,

Where a and b are odd positive integers.

If two positive integers are odd, then their sum, difference and sum of their squares are always even.

∴ (a - b) (a + b) and $(a^2 + b^2)$ are divisible by 2.

Hence (a - b) (a + b) x $(a^2 + b^2) = a^4 - b^4$ is always divisible by $2^3 = 8$

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Read more divide multiple add subtract Based Quantitative Aptitude Questions and Answers

Question : 1

The greatest common divisor of 33333 + 1 and 33334 + 1 is ?

a) 2

b) 1

c) 33333 + 1

d) 20

Answer: (c)

Question : 2

A number when divided by 91 gives a remainder 17. When the same number is divided by 13, the remainder will be ?

a) 0

b) 4

c) 6

d) 3

Answer: (b)

Here, the first divisor (91) is a multiple of the second divisor (13).

∴ Required remainder = Remainder obtained on dividing 17 by 13

⇒ 17 = ( 13 × 1 ) + 4

Hence Required remainder = 4

Question : 3

Each member of a picnic party contributed twice as many rupees as the total number of members and the total collection was 3042. The number of members present in the party was ?

a) 2

b) 32

c) 40

d) 39

Answer: (d)

Let the total number of members be X.

Then, each member's contribution =Rs. 2X

Given, X × 2X = 3042

⇒ 2X= 3042

⇒ X= 1521

⇒ X = 39

Question : 4

(49)15 – 1 is exactly divisible by :

a) 50

b) 51

c) 29

d) 8

Answer: (d)

As we know, xn – an is exactly divisible by (x – a) if n is odd.

∴ (49)15 – (1 )15 is exactly divisible by 49 – 1 = 48, that is a multiple of 8.

Hence required answer is 8.

Question : 5

When a number is divided by 56, the remainder obtained is 29. What will be the remainder when the number is divided by 8 ?

a) 4

b) 5

c) 3

d) 7

Answer: (b)

When the second divisor is a factor of the first divisor, the second remainder is obtained by dividing the first remainder by the second divisor.

Hence, on dividing 29 by 8, the remainder is 5.

Question : 6

If m and n are positive integers and (m – n) is an even number, then (m2 – n2) will be always divisible by

a) 4

b) 6

c) 8

d) 12

Answer: (a)

In this problem, put any even positive value for both m & n,

For example m = 4 & n = 2

∴ (m2 – n2) = (42 – 22) = 16 - 4

= 12 is always divisible by 4.

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