type 4 difference & equality of si rate & years Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 6 EXERCISES

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The following question based on simple interest topic of quantitative aptitude

Questions : The difference between simple interest and the true discount on Rs. 2400 due 4 years hence at 5% per annum simple interest is

(a) Rs.70

(b) Rs.30

(c) Rs.50

(d) Rs.80

The correct answers to the above question in:

Answer: (d)

Using Rule 1,

True discount

= $\text"Amount × Rate × Time"/ \text"100 +(Rate × Time)"$

= ${2400 × 5 × 4}/{100 + (5 × 4)}$

= ${2400 × 5 × 4}/120$ = Rs.400

S.I. = ${2400 × 5 × 4}/100$ = Rs.480

Required difference

= Rs.(480 - 400) = Rs.80

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Read more difference equality in si rate years Based Quantitative Aptitude Questions and Answers

Question : 1

A sum of Rs.1500 is lent out in two parts in such a way that the simple interest on one part at 10% per annum for 5 years is equal to that on another part at 12.5% per annum for 4 years. The sum lent out at 12.5% is :

a) Rs.1000

b) Rs.500

c) Rs.1250

d) Rs.750

Answer: (d)

Using Rule 1,

Let the sum lent out at 12.5% be x

Sum lent out at 10% = 1500 - x

Now, ${(1500 - x) × 10 × 5}/100$

= ${x × 12.5 × 4}/100$

50 (1500 - x ) = 50x

2x = 1500

$x = 1500/2$ = Rs.750

Question : 2

Mohan lent some amount of money at 9% simple interest and an equal amount of money at 10% simple interest each for two years. If his total interest was Rs. 760, what amount was lent in each case ?

a) Rs.1800

b) Rs.1700

c) Rs.2000

d) Rs.1900

Answer: (c)

Using Rule 1,

Let the sum lent in each case be x.

Then, ${x × 9 × 2}/100 + {x × 10 × 2}/100$ = 760

${x × 2}/100$(9 + 10) = 760

${2 × 19x}/100$ = 760

$x = {760 × 100}/{2 × 19}$ = Rs.2000

Question : 3

Simple interest on Rs.500 for 4 years at 6.25% per annum is equal to the simple interest on Rs.400 at 5% per annum for a certain period of time. The period of time is

a) 5 years

b) 4 years

c) 8$2/3$ years

d) 6$1/4$ years

Answer: (d)

Using Rule 1,

Let the period of time be T years. Then,

${400 × 5 × T}/100 = {500 × 4 × 6.25}/100$

T = ${500 × 4 × 6.25}/{400 × 5}$

= $25/4 = 6{1}/4$ years

Question : 4

In how many years will the simple interest on a sum of money be equal to the principal at the rate of 16$2/3$% per annum ?

a) 5 years

b) 4 years

c) 8 years

d) 6 years

Answer: (d)

Using Rule 1,

Let the principal be x.

Time = $\text"SI × 100"/\text"Principal × Rate"$

= ${x × 100 × 3}/{x × 50}$ = 6 years

Question : 5

Equal sum of money are lent to X and Y at 7.5% per annum for a period of 4 years and 5 years respectively. If the difference in interest, paid by them was Rs.150, the sum lent to each was

a) Rs.1000

b) Rs.500

c) Rs.3000

d) Rs.2000

Answer: (d)

Let the sum lent be x.

${x × 7.5 × 5}/100 - {x × 7.5 × 4}/100 = 150$

${x × 7.5 × 1}/100$ = 150

$x = {150 × 100}/{7.5}$ = Rs.2000

Using Rule 13,

Here, $P_1 = P, R_1 = 7.5%, T_1$ = 4 years.

$P_2 = P, R_2 = 7.5%, T_2$ = 5 years.

S.I. = Rs.150

S.I. = ${P_2R_2T_2 - P_1R_1T_1}/100$

150 = ${P × 7.5 × 5 - P × 7.5 × 4}/100$

15000 = 7.5P

P = $15000/{7.5}$

P = $150000/75$ = Rs.2000

Question : 6

A sum of Rs.1750 is divided into two parts such that the interests on the first part at 8% simple interest per annum and that on the other part at 6% simple interest per annum are equal. The interest on each part (In rupees) is

a) 65

b) 60

c) 40

d) 70

Answer: (b)

Using Rule 1,

Let first part be x and second part be(1750 –x )

According to the question,

x × $8/100 = (1750 - x ) × 6/100$

8x + 6x = 1750 × 6

14x = 1750 × 6

$x = {1750 × 6}/14$ = Rs.750

Interest = 8% of 750

= 750 × $8/100 = Rs.60

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