type 4 difference & equality of si rate & years Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 6 EXERCISES

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The following question based on simple interest topic of quantitative aptitude

Questions : The simple interest on a sum of money is $1/4$th of the principal and the number of years is equal to rate per cent per annum. The rate per cent is

(a) 5%

(b) 2.5%

(c) 10%

(d) 7.5%

The correct answers to the above question in:

Answer: (a)

Let the principal be x and rate be y% per annum.

According to the question,

SI = ${P × R × T}/100$

$x/4 = {x × y × y}/100$

$y^2 = 100/4$ = 25

y = $√{25}$ = 5% per annum

Using Rule 5,

n = $1/5$, R = T

RT = n × 100

$R^2 = 1/4 × 100$ = 25

R = 5%

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Read more difference equality in si rate years Based Quantitative Aptitude Questions and Answers

Question : 1

A sum of Rs.1750 is divided into two parts such that the interests on the first part at 8% simple interest per annum and that on the other part at 6% simple interest per annum are equal. The interest on each part (In rupees) is

a) 65

b) 60

c) 40

d) 70

Answer: (b)

Using Rule 1,

Let first part be x and second part be(1750 –x )

According to the question,

x × $8/100 = (1750 - x ) × 6/100$

8x + 6x = 1750 × 6

14x = 1750 × 6

$x = {1750 × 6}/14$ = Rs.750

Interest = 8% of 750

= 750 × $8/100 = Rs.60

Question : 2

Equal sum of money are lent to X and Y at 7.5% per annum for a period of 4 years and 5 years respectively. If the difference in interest, paid by them was Rs.150, the sum lent to each was

a) Rs.1000

b) Rs.500

c) Rs.3000

d) Rs.2000

Answer: (d)

Let the sum lent be x.

${x × 7.5 × 5}/100 - {x × 7.5 × 4}/100 = 150$

${x × 7.5 × 1}/100$ = 150

$x = {150 × 100}/{7.5}$ = Rs.2000

Using Rule 13,

Here, $P_1 = P, R_1 = 7.5%, T_1$ = 4 years.

$P_2 = P, R_2 = 7.5%, T_2$ = 5 years.

S.I. = Rs.150

S.I. = ${P_2R_2T_2 - P_1R_1T_1}/100$

150 = ${P × 7.5 × 5 - P × 7.5 × 4}/100$

15000 = 7.5P

P = $15000/{7.5}$

P = $150000/75$ = Rs.2000

Question : 3

In how many years will the simple interest on a sum of money be equal to the principal at the rate of 16$2/3$% per annum ?

a) 5 years

b) 4 years

c) 8 years

d) 6 years

Answer: (d)

Using Rule 1,

Let the principal be x.

Time = $\text"SI × 100"/\text"Principal × Rate"$

= ${x × 100 × 3}/{x × 50}$ = 6 years

Question : 4

The simple interest on a sum of money is $1/9$ of the principal and the number of years is equal to rate per cent per annum. The rate per annum is

a) $1/3$%

b) 3%

c) $3/10$%

d) 3$1/3$%

Answer: (d)

$\text"Simple interest"/ \text"Principal" = 1/9$

If the annual rate of interest be r%, then

Rate = $\text"S.I. × 100"/ \text"Principal × Time"$

$r = 1/9 × 100/r$

$r^2 = 100/9$

r = $√{100/9} = 10/3 = 3{1}/3$%

Using Rule 5,

Here, n = $1/9$, R = T

RT = n × 100

$R^2 = 1/9 × 100 = 100/9$

R = $√{100/9} = 10/3 = 3{1}/3$%

Question : 5

The difference between the simple interest received from two different sources on Rs.1500 for 3 years is Rs.13.50. The difference between their rates of interest is:

a) 0.2%

b) 0.1%

c) 0.4%

d) 0.3%

Answer: (d)

Let $r_1$, and $r_2$ be the required rate of interest

Then, ${13.50} = {1500 × 3 × r_1}/100$

– ${1500 × 3 × r_2}/100 = 4500/100(r_1 - r_2)$

$r_1 - r_2 = 135/450 = 27/90$

= $3/10$ = 0.3%

Using Rule 13,

$P_1 = Rs.1500, R_1 , T_1$ = 3 years.

$P_2 = Rs.1500, R_2 , T_2$ = 3 years.

S.I. = Rs.13.50

13.50 = ${1500 × R_2 × 3 - 1500 × R_1 × 3}/100$

$1350/100 = {4500(R_2 - R_1)}/100$

$R_2 - R_1 = 1350/4500 = 27/90$

= $3/10$ = 0.3%

Question : 6

The simple interest on a certain sum for 8 months at 4% per annum is Rs.129 less than the simple interest on the same sum for 15 months at 5% per annum. The sum is :

a) Rs.2400

b) Rs.2,580

c) Rs.3600

d) Rs.2529

Answer: (c)

Let the sum be x

${x × 5 × 15}/{100 × 12} - {x × 4 × 8}/{100 × 12}$ = 129

$x/{100 × 12}$(75 - 32) = 129

$x = {129 × 1200}/43$ = Rs.3600

Using Rule 13,

$P_1 = P, R_1 = 4%$

$T_1 = 8 months = 8/12$ years

$P_2 = P, R_2$ = 5%

$T_2 = 15 month = 15/12$ years

S.I. = Rs.129

129 = ${P × 5 × 15/12 - P × {4 × 8}/12}/100$

12900 = ${75P - 32P}/12$

12900 = ${43P}/12$

P = Rs.3600

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