type 9 coins & rupees based ratio & proportion problems Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on ratio & proportion topic of quantitative aptitude
(a) 100
(b) 135
(c) 120
(d) 80
The correct answers to the above question in:
Answer: (c)
Ratio of values of 50 paise, 25 paise and 10 paise coins
= $2/2 : 3/4 : 5/10$
= $1 : 3/4 : 1/2$ = 4 : 3 : 2
Sum of the ratios = 4 + 3 + 2 = 9 Value of 25 paise coins
= $3/9 × 90$ = Rs.30
Number of 25 paise coins
= 30 × 4 = 120
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Read more coins and rupees based problems Based Quantitative Aptitude Questions and Answers
Question : 1
There are 225 consisting of one rupee, 50 paise and 25 paise coins. The ratio of their numbers in that order is 8 : 5 : 3. The number of one-rupee coins is :
a) 160
b) 172
c) 112
d) 80
Answer »Answer: (a)
Ratio of the number of coins
= 8 : 5 : 3
Ratio of their values
= $8 : 5/2 : 3/4$ = 32 : 10 : 3
Sum of the ratios
= 32 + 10 + 3 = 45
Value of one rupee coins
= $32/45 × 225$ = Rs.160
Number of one rupee coins = 160
Question : 2
If 378 coins consist of rupees, 50 paise and 25 paise coins, whose values are in the ratio of 13 : 11 : 7, the number of 50 paise coins will be :
a) 136
b) 133
c) 128
d) 132
Answer »Answer: (d)
The ratio of values of rupee, 50 paise and 25 paise coins
= 13 : 11 : 7
Ratio of their numbers
= 13 × 1 : 11 × 2 : 7 × 4
= 13 : 22 : 28
Sum of the ratios
= 13 + 22 + 28 = 63
Required number of 50 paise coins
= $22/63 × 378$ = 132
Question : 3
A box has 210 coins of denominations one-rupee and fifty paise only. The ratio of their respective values is 13 : 11. The number of one-rupee coins is
a) 77
b) 78
c) 66
d) 65
Answer »Answer: (b)
Respective ratio of the number of coins
= 13 : 11 × 2 = 13 : 22
Number of 1 rupee coins
= $13/{13 + 22} × 210$
= $13/35 × 210 = 78$
Question : 4
In a bag, there are three types of coins — 1-rupee, 50 paise and 25-paise in the ratio of 3 : 8 : 20. Their total value is 372. The total number of coins is
a) 744
b) 612
c) 961
d) 1200
Answer »Answer: (c)
Ratio of the number of coins of Re. 1, 50 paise and 25 paise
= 3 : 8 : 20
Ratio of the values of these coins
= $3 : 8/2 : 20/4$ = 3 : 4 : 5
Value of 1 rupee coins
= $3/12 × $372 = Rs.93
Value of 50 paise coins
= $4/12 × 372$ = Rs.124
Value of 25 paise coins
= $5/12$ × 372 = Rs.155
Number of coins
= 93 + 124 × 2 + 155 × 4
= 93 + 248 + 620 = 961
Question : 5
A boy has a few coins of denominations 50 paise, 25 paise and 10 paise in the ratio 1 : 2 : 3. If the total amount of the coins is 6.50, the number of 10 paise coins is
a) 15
b) 20
c) 10
d) 5
Answer »Answer: (a)
Ratio of the value of coins
= $1/2 : 2/4 : 3/10$ = 5 : 5 : 3
Value of the 10-paise coins
= Rs.$(3/13 × 6.50)$ = Rs.1.5
Number of 10-paise coins
= 1.5 × 10 = 15
Question : 6
A box contains 56 in the form of coins of one rupee, 50 paise and 25 paise. The number of 50 paise coins is double the number of 25 paise coins and four times the number of one rupee coins. How many 50 paise coins are there in the box?
a) 32
b) 16
c) 64
d) 52
Answer »Answer: (c)
Number of 1-rupee coins = x
Number of 50 paise coins = 4x
Number of 25 paise coins = 2x
Ratio of their values
= $x : {4x}/2 : {2x}/4$ = 2 : 4 : 1
Value of 50-paise coins
= $4/7 × 56$ = Rs.32
Their number = 32 × 2 = 64
(x )(1)+(4x ) $(1/2)+(2x)(1/4)$= 56
x + 2x + $1/2$x =56
$x = 56 × 2/7$ =16
No. of 50p coins
= 4 × 16 = 64.
GET ratio & proportion PRACTICE TEST EXERCISES
type 1 basic concepts of ratio & proportion
type 2 age based ratio & proportion problems
type 3 addition subtraction product on ratio & proportion
type 4 income & expenditure based ratio & proportion problems
type 5 shares & partnership based ratio & proportion problems
type 6 fractions based ratio & proportion problems
type 7 finding sum difference product based ratio & proportion problems
type 8 alligation & mixtures based ratio & proportion problems
type 9 coins & rupees based ratio & proportion problems
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