Model 1 Basics on Time & Work Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (c)

According to question,

10 men’s one day’s work = $1/12$

1 man one day’s work =$1/{12 × 10} = 1/120$

Similarly, 1 woman one day’s work = $1/{6 × 10} = 1/60$

(1 man + 1 woman)’s one day’s work = $1/120 + 1/60$

= ${1 + 2}/120 = 3/120 = 1/40$

(10 men + 10 women)’s one day’s work = $10/40 = 1/4$

Therefore, both the teams can finish the whole work in 4 days.

Answer: (b)

(P + Q)’s 1 day’s work = $1/12$ ...(i)

(Q + R)’s 1 day’s work = $1/15$ ...(ii)

(R + P)’s 1 day’s work = $1/20$ ...(iii)

Adding all three equations,

2 (P + Q + R)’s 1 day’s work = $1/12 + 1/15 + 1/20$

${5 + 4 + 3}/60 = 12/60 = 1/5$

(P + Q + R)’s 1 day’s work = $1/10$ ...(iv)

P’s 1 day’s work = $1/10 - 1/15 = {3 - 2}/30 = 1/30$

P alone will complete the work in 30 days.

Answer: (b)

According to question,

A and B can do a work in 12 days

(A + B)'s one day's work = $1/12$

Similarly, (B + C)'s one day's work = $1/15$

and (C + A)'s one day's work = $1/20$

On adding all three,

2 (A + B + C)'s one days's work

= $1/12 + 1/15 + 1/20 = {10 + 8 + 6}/120 = 1/5$

(A + B + C)'s one days's work = $1/10$

A, B and C together can finish the whole work in 10 days.

Time taken = ${2 × 12 × 15 × 20}/{12 × 15 + 15 × 20 + 20 × 12}$

= ${24 × 300}/{180 + 300 + 240} = 7200/720$ = 10 days.