Model 1 Basic Time & Distance using formula Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 5 EXERCISES
The following question based on time & distance topic of quantitative aptitude
(a) 15
(b) 12.5
(c) 12
(d) 10
The correct answers to the above question in:
Answer: (b)
Using Rule 1,
Speed = $\text"Distance"/\text"Time" = 250/75$
= $10/3$ m/sec = $10/3 × 18/5$ km/hr
[Since, 1 m/s = $18/5$ km/hr]
= 2 × 6 km/hr. = 12 km/hr.
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Read more basic problems formulas Based Quantitative Aptitude Questions and Answers
Question : 1
The speed 3$1/3$ m/sec when expressed in km/hour becomes
a) 12
b) 10
c) 9
d) 8
Answer »Answer: (a)
Since, 1 m/sec = $18/5$ kmph
$10/3$ m/sec
= $18/5 × 10/3$ = 12 kmph
Question : 2
An aeroplane covers a certain distance at a speed of 240 km hour in 5 hours. To cover the same distance in 1$2/3$ hours, it must travel at a speed of :
a) 720 km./hr.
b) 600 km./hr.
c) 360 km./hr.
d) 300 km./hr.
Answer »Answer: (a)
Using Rule 1,
Let the required speed is x km/ hr
Then, $240 × 5 = 5/3 × x$
x = 720 km/hr.
Question : 3
The speed of a bus is 72 km/hr. The distance covered by the bus in 5 seconds is
a) 74.5 m
b) 50 m
c) 60 m
d) 100 m
Answer »Answer: (d)
Using Rule 1,
Speed of bus = 72 kmph
= $({72 × 5}/18)$ metre/second
= 20 metre/second
∴ Required distance
= 20 × 5 = 100 metre
Question : 4
A man walks 'a' km in 'b' hours. The time taken to walk 200 metres is
a) ${ab}/200$ hours
b) $b/a$ hours
c) $b/{5a}$ hours
d) ${200b}/a$ hours
Answer »Answer: (b)
Using Rule 1,
Man's speed = $\text"Distance"/ \text"Time"$
= $a/b$ kmph = ${1000a}/b$ m/hour
Time taken in walking 200 metre
= $200/{{1000a}/b} =b/{5a}$ hours
Question : 5
A bullock cart has to cover a distance of 120 km. in 15 hours. If it covers half of the journey in $3/5$th time, the speed to cover the remaining distance in the time left has to be
a) 15 km/hr
b) 10 km/hr
c) 6.67 km/hr
d) 6.4 km/hr
Answer »Answer: (c)
Using Rule 1,
Remaining time
= $2/5 × 15 = 6$ hours
Required speed
= $60/6$ = 10 kmph
Question : 6
A man travelled a distance of 80 km in 7 hrs partly on foot at the rate of 8 km per hour and partly on bicycle at 16km per hour. The distance travelled on the foot is
a) 44 km
b) 36 km
c) 48 km
d) 32 km
Answer »Answer: (d)
Journey on foot=x km
Journey on cycle = (80 –x)km
$x/8 + {80 - x}/16 = 7$
${2x + 80 - x}/16 = 7$
x + 80 = 16 × 7 = 112
x= 112 - 80 = 32 km.
Using Rule 13,Let a man take 't' hours to travel 'x' km. If he travels some distance on foot with the speed u km/h and remaining distance by cycle with the speed v km/h,then time taken to travel on foot.Time = ${(vt - x)}/{(v - u)}$Distance travelled on foot = Time × u
Here, x = 80, t = 7, u = 8, v = 16
Time = $({vt - x}/{v - u})$
=$({16 × 7 - 80}/{16 - 8})$
=$({112 - 80}/8) = 32/8$ = 4 hrs
Distance travelled
= 4 × 8 = 32 kms
GET time & distance PRACTICE TEST EXERCISES
Model 1 Basic Time & Distance using formula
Model 2 Vehicles in x/y of its usual speed
Model 3 Problems on average speed
Model 4 Time & Distance with Ratios
Model 5 Problems with Races
time & distance Shortcuts and Techniques with Examples
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Model 1 Basic Time & Distance using formula
Defination & Shortcuts … -
Model 2 Vehicles in x/y of its usual speed
Defination & Shortcuts … -
Model 3 Problems on average speed
Defination & Shortcuts … -
Model 4 Time & Distance with Ratios
Defination & Shortcuts … -
Model 5 Problems with Races
Defination & Shortcuts …
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