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The following question based on number system topic of quantitative aptitude
(a) xyzw
(b) wzyx
(c) x + 10y + 100z + 1000w
(d) $10^3$x + $10^2$y + 10z + w
The correct answers to the above question in:
Answer: (d)
In this problem, the digits of the number from the left are x, y, z and w respectively.
So, x is at thousands places, y is at hundreds of places, z is at tens place and w is at ones place.
Thus, the required number be
= (1000×x) + (100×y) + (10×z) + (1×w)
= (1000x + 100y + 10z + w)
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Read more basic number system Based Quantitative Aptitude Questions and Answers
Question : 1
If n and p are both odd numbers, which of the following is an even number?
a) n + p
b) n + p + 1
c) np + 2
d) np
Answer »Answer: (a)
Let for example:
n=3 p=5
Option a) 3 + 5 = 8 (even number)
Option b) 3 + 5 + 1 = 9 (odd number)
Option c) 3 x 5 + 2 = 17 (odd number)
Option d) 3 x 5 = 3 (odd number)
Question : 2
For the integer n, if $n^3$ is odd, then which of the following statements are true? I. n is odd. II. $n^2$ is odd. III. $n^2$ is even
a) I only
b) II only
c) I and II only
d) I and III only
Answer »Answer: (c)
If n3 is odd
⇒ n is odd and n2 is odd
For example
$n^3$ = 27. Then n = 3 & $n^2$ = 9
∴ I and II are true.
Question : 3
If (n - 1) is an odd number, what are the two other odd numbers nearest to it?
a) n, n-1
b) n, n-2
c) n - 3, n + 1
d) n - 3, n + 5
Answer »Answer: (c)
(n – 1) is odd
⇒ (n – 1) – 2 & (n – 1) + 2 are odd.
⇒ (n – 3) and (n + 1) are odd.
Question : 4
If x, y, z be the digits of a number beginning from the left, the number is
a) xyz
b) x + 10y + 100z
c) 10x + y + 100z
d) 100x + 10y + z
Answer »Answer: (d)
In this problem, the digits of the number from the left are x, y and z respectively.
So, x is at hundreds places, y is at tens place and z is at ones place.
Thus, the required number be
= (100×x) + (10×y) + (1×z)
= (100x + 10y + z)
Question : 5
If n is an integer between 20 and 80, then any of the following could be n+7 except
a) 47
b) 58
c) 84
d) 88
Answer »Answer: (d)
Given, 20 < n < 80
Now n + 7 = ?
20 + 7 < n + 7 < 80 + 7
i.e., 27 < n + 7 < 87
∴ 88 does not lies between 27 to 87.
Question : 6
P and Q are two positive integers such that PQ = 64. Which of the following cannot be the value of P + Q?
a) 16
b) 20
c) 35
d) 65
Answer »Answer: (c)
The possible combinations of (P, Q)
So that the product is 64 are
(1, 64), (2, 32), (4, 16) and (8, 8)
∴ P+Q cannot be 35
GET number system PRACTICE TEST EXERCISES
model 1 basic number system
model 2 divisibility, multiples, add and subtract based number system
model 3 fraction of numbers
model 4 finding unit place of a number
model 5 smallest and largest fraction/numbers
model 6 operations of consecutive numbers (odd, even, square, etc.)
number system Shortcuts and Techniques with Examples
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model 1 basic number system
Defination & Shortcuts … -
model 2 divisibility, multiples, add and subtract based number system
Defination & Shortcuts … -
model 3 fraction of numbers
Defination & Shortcuts … -
model 4 finding unit place of a number
Defination & Shortcuts … -
model 5 smallest and largest fraction/numbers
Defination & Shortcuts … -
model 6 operations of consecutive numbers (odd, even, square, etc.)
Defination & Shortcuts …
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