find a day with reference day Detailed Explanation And More Example

Answer: (b)

According to the question,

26^th January to 31^st January = 6 days  

February = 28 days   

March = 31 days  

April = 30 days

May = 31 days  

June = 30 days  

July =31 days  

August = 31 days   

1^st September to 23^rd September 23 days  

Total days = 241

∴ Required days = 241

Answer: (c)

4^th Saturday = 22^nd day

3^rd Saturday = 22 - 7 = 15^th day

∴ 13^th day - Saturday - 2 = Thursday

Answer: (b)

Tomorrow = Friday

3 days after tomorrow = 15^th June = Friday + 3 odd days = Monday

Days from 15^th to 30^th June = 15

15 ÷ 7 = 7)15(2 =>remainder 1 odd day

30^th June = Monday + 1 odd day = Tuesday

Answer: (b)

2007 is an ordinary year and in an ordinary year 1^st January = 31^st December

As, 1^st January = Monday  

∴  31^st December = Monday

∴  1^st January 2008 = Monday + 1odd day = Tuesday

Answer: (a)

In a leap year, Last day = 1^st day + 1 odd day (remember)

As given, 1^st day = Wednesday  

Last day = Wednesday + 1 odd day = Thursday

Answer: (c)

The year 2001 was an ordinary year and in an ordinary year 1^st day = Last day  

(remember) 1^st January = 31^st December   

As, given that, 1^st January = Monday 

Hence, 31^st December = Monday