find a day with reference day Detailed Explanation And More Example

Answer: (a)

In a leap year, Last day = 1^st day + 1 odd day (remember)

As given, 1^st day = Wednesday  

Last day = Wednesday + 1 odd day = Thursday

Answer: (b)

2007 is an ordinary year and in an ordinary year 1^st January = 31^st December

As, 1^st January = Monday  

∴  31^st December = Monday

∴  1^st January 2008 = Monday + 1odd day = Tuesday

Answer: (c)

Since 2008 is a leap year.

In a leap year, last day = 1^st day 1 + odd day

= Tuesday + 1 odd day

= Wednesday = 31^st December

∴  1^st January, 2009 = Wednesday + 1 odd day = Thursday

Answer: (c)

The year 2008 is a leap year.

So, it has 2 odd days.

1^st day of the year 2008 is Tuesday (Given)

So, 1^st day of the year 2009 is 2 beyond Tuesday.

Hence, it will be Thursday.

Answer: (b)

The year 2004 is a leap year.

So, it has 2 odd days.

Therefore, The day of 6^th March 2005 will be 2 days beyond the day on 6^th March 2004.

But, 6^th march, 2005 is Monday.

Therefore, 6^th March 2004 is Saturday.

Answer: (b)

The year 2007 is an ordinary year.

So, it has 1 odd day.

1^st day of the year 2007 was Monday.

1^st day of the year 2008 will be 1 day beyond Monday.

Hence, it will be Tuesday.