find a day with reference day Detailed Explanation And More Example

Answer: (b)

The year 2004 is a leap year.

So, it has 2 odd days.

Therefore, The day of 6^th March 2005 will be 2 days beyond the day on 6^th March 2004.

But, 6^th march, 2005 is Monday.

Therefore, 6^th March 2004 is Saturday.

Answer: (c)

The year 2008 is a leap year.

So, it has 2 odd days.

1^st day of the year 2008 is Tuesday (Given)

So, 1^st day of the year 2009 is 2 beyond Tuesday.

Hence, it will be Thursday.

Answer: (c)

The year 2001 was an ordinary year and in an ordinary year 1^st day = Last day  

(remember) 1^st January = 31^st December   

As, given that, 1^st January = Monday 

Hence, 31^st December = Monday

Answer: (d)

The year 2006 is an ordinary year.

So, it has 1 odd day.

So, the day of 8^th Dec 2007 will be 1 day beyond the day on 8^th Dec 2006.

But, 8^th Dec 2007 is Saturday.

Therefore, 8^th Dec 2006 is Friday.

Answer: (c)

Fifteen days from 21^st will be 26^th and Monday lies on 3^rd, 10^th, 17^th, 24^th.

So, the day on 26^th will be Wednesday.

Answer: (b)

Number of days in 1996 (366-26) = 340

Number of days in 1997 = 365

Number of days in 1998 = 365

Number of days in 1999 = 365 

Number of days from January 2000 to July 2000 = 31 + 29 + 31 + 30 + 31 + 30 + 31

= 213 

Number of days from 1^st to 15^th August, 2000 = 15

∴ Total days = 340 + 365 + 365 + 365 + 213 + 15 = 1663

∴ 1663 ÷ 7 = remainder 4

∴ 1663 days = (237 X 7 + 4) days = 237 weeks + 4 days

∴  Number of odd days = 4

∴  Day on 15^th August, 2000 = Friday + 4 Odd days = Tuesday