basic calendar problems Detailed Explanation And More Example

Answer: (c)

The dates of three of the Sundays are even number is 2, 9, 16, 23, 30.

So, on 16th of that month = Sunday,

15th of that month falls on a Saturday.

Answer: (a)

Answer: (c)

The year 1990 has 365 days. i.e. 1 odd day,

the year 1991 has 365 days, i.e. 1 odd day,

the year 1992 has 366 days i.e. 2 odd days.

The likewise year 1993, 1994, 1995 have 1 odd day each.

The sum of odd days, so calculated from years 1990 - 95

= (1 + 1 + 2 + 1 + 1 + 1) = 7 days = 0 odd day

Hence, the year 1996 will have the same calendar as that of the year 1990.

Answer: (b)

Answer: (d)

Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd days.

Sum = 14 odd days = 0 odd day.

Therefore, Calendar for the year 2018 will be the same as for the year 2007.

Answer: (a)

Number of days left in the month after 16th = 31 - 16 = 15

Number of odd days = 15/7 = 2 weeks + 1 odd day

Therefore, Required day = Thursday + 1 odd day = Friday

As, 16th of the month is third Thursday, the day which is two weeks after this day is fifth Thursday.

So, one day after 5th Thursday is 5th Friday.