basic calendar problems Detailed Explanation And More Example

Answer: (b)

Answer: (c)

Answer: (c)

The dates of three of the Sundays are even number is 2, 9, 16, 23, 30.

So, on 16th of that month = Sunday,

15th of that month falls on a Saturday.

Answer: (a)

Number of days left in the month after 16th = 31 - 16 = 15

Number of odd days = 15/7 = 2 weeks + 1 odd day

Therefore, Required day = Thursday + 1 odd day = Friday

As, 16th of the month is third Thursday, the day which is two weeks after this day is fifth Thursday.

So, one day after 5th Thursday is 5th Friday.

Answer: (d)

There are months of 30, 31 and 28 days and last day of the month are Wednesday.

So, using 28 and 30 days, there are 4 Mondays.

Using 31 days, there are 5 Mondays

So, it cannot be specified.

Answer: (b)

1977 is an ordinary year.

We know that the calendar of an ordinary year repeats after 6 yrs or 11 yrs.

Let us check for the number of odd days in 6th and 11th years.

From the above table, Number of odd days from 18.09.1977 to 18.09.1983 = 7,

i.e., 0 odd days

It means that in 1983, 18th September would fall on Sunday.

From the above table, a number of odd days from 18.09.1977 to 18.09.1988 = 14

i.e., 0 odd days.

Now, it is clear that 2 marriage anniversaries would fall on Sunday in the next 15 yr.