SBI PO 2019 Questions and Answers Detailed Explanation

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The following question based on SBI PO topic of previous year question answers

Questions : Cost of gardening the circular field C at Rs.10 per meter square is Rs.3465. Side of the square field S is equals to the diameter of the circular field C. find the perimeter of square field.

(a) 108

(b) 84 m

(c) 78 m

(d) 112 m

e) None of these

The correct answers to the above question in:

Answer: (b)

Let r meter be the radius of circular field C, then

Area of circular field C × 10 = 3465

⇒ πr 2 × 10 = 3465

⇒ r 2 = $441/4$

⇒ r = $21/2$ m

Side of square field S = 2 × r = 21m

Perimeter of square field = 4 × 21 = 84 meters

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Question : 1

4 years ago, the ratio of ages of A and B was 9 : 11 and 6 years hence, the ratio of ages of A and B will be 7 : 8. Find the present age of B.

a) 22 years

b) 24 years

c) 26 years

d) 37 years

e) None of these

Answer: (c)

Let the ages of A and B be 9X and 11X, then

According to the question:

$\text"9X + 10" / \text"11X + 10"$ =$7/8$

⇒ 72X + 80 = 77X + 70

⇒ X = 2

Hence, the present age of B = 11X + 4 = 22 + 4 = 26 years

Question : 2

The cost price of the two chairs is same. Difference between their selling prices is Rs. 90. On selling one chair, a person got a profit of 12% and on selling another he got a profit of 18%. Find the cost price of each chair.

a) Rs. 1200

b) Rs. 1500

c) Rs. 1800

d) Rs. 2400

e) Rs. 1000

Answer: (b)

Let CP of the Article 100x Rs.

So SP of first Article at 12% gain= 112x Rs.

And SP of second Article at 18% gain = 118x Rs.

ATQ,

118x – 112x= 90

6x = 90

X= 15

So CP of the Article = 100x =1500 Rs

Question : 3

40 men can complete a work in 48 days. If 64 men started working and after X days, 32 more men joined the work. If the remaining work is completed in 16$2/3$ days, then find the value of X.

a) 2

b) 5

c) 8

d) 4

e) 6

Answer: (b)

By MDW formula,

Total work = 48× 40 = 1920 units

Now,

1920 = 64 × X + (64 + 32) × (50/3)

⇒ 1920 = 64X + 1600

⇒ 64X = 320

⇒ X = 5

Question : 4

4 years hence the sum of ages of A and B will be 16 years more than the sum of the present ages of B and C. 4 years ago the sum of A’s age and C’s age was 32 years, then what is the present age of C?

a) 18 years

b) 14 years

c) 10 years

d) 16 years

e) 12 years

Answer: (d)

According to the question:

Present age of A and C:

A + C = 40 ............(i)

After 4 years, sum of ages of A and B will be 16 years more than the sum of the present ages of B and C.

A + 4 + B + 4 = B + C + 16

A - C = 8 ............(ii)

On solving eq(i) and eq(ii).

2A = 48

A = 24

Then, the present age of C:

24 + C = 40

C = 16 Years

Question : 5

The ratio of speed of a boat in still water to speed of the current is 10 : 1. If ratio of the time taken by the boat to travel D km downstream to the time taken to travel (D – 45) km upstream is 3 : 2. Find the value of D.

a) 88

b) 54

c) 110

d) 99

e) 66

Answer: (d)

Let ratio of speed of a boat in still water to speed of the current is 10x : x,

then

$\text"D / ( 10+1 ) x" /\text "D - 45/ ( 10 - 1) x"$=$3/2$

⇒ 18D = 33D – 33 × 45

⇒ 15D = 33 × 45

⇒ D = 99

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