SBI PO 2019 Questions and Answers Detailed Explanation
MOST IMPORTANT previous year question answers - 1 EXERCISES
The following question based on SBI PO topic of previous year question answers
(a) 2
(b) 5
(c) 8
(d) 4
e) 6
The correct answers to the above question in:
Answer: (b)
By MDW formula,
Total work = 48× 40 = 1920 units
Now,
1920 = 64 × X + (64 + 32) × (50/3)
⇒ 1920 = 64X + 1600
⇒ 64X = 320
⇒ X = 5
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Read more sbi po prelims 2019 Based Previous Year Questions and Answers
Question : 1
Cost of gardening the circular field C at Rs.10 per meter square is Rs.3465. Side of the square field S is equals to the diameter of the circular field C. find the perimeter of square field.
a) 108
b) 84 m
c) 78 m
d) 112 m
e) None of these
Answer »Answer: (b)
Let r meter be the radius of circular field C, then
Area of circular field C × 10 = 3465
⇒ πr 2 × 10 = 3465
⇒ r 2 = $441/4$
⇒ r = $21/2$ m
Side of square field S = 2 × r = 21m
Perimeter of square field = 4 × 21 = 84 meters
Question : 2
4 years ago, the ratio of ages of A and B was 9 : 11 and 6 years hence, the ratio of ages of A and B will be 7 : 8. Find the present age of B.
a) 22 years
b) 24 years
c) 26 years
d) 37 years
e) None of these
Answer »Answer: (c)
Let the ages of A and B be 9X and 11X, then
According to the question:
$\text"9X + 10" / \text"11X + 10"$ =$7/8$
⇒ 72X + 80 = 77X + 70
⇒ X = 2
Hence, the present age of B = 11X + 4 = 22 + 4 = 26 years
Question : 3
The cost price of the two chairs is same. Difference between their selling prices is Rs. 90. On selling one chair, a person got a profit of 12% and on selling another he got a profit of 18%. Find the cost price of each chair.
a) Rs. 1200
b) Rs. 1500
c) Rs. 1800
d) Rs. 2400
e) Rs. 1000
Answer »Answer: (b)
Let CP of the Article 100x Rs.
So SP of first Article at 12% gain= 112x Rs.
And SP of second Article at 18% gain = 118x Rs.
ATQ,
118x – 112x= 90
6x = 90
X= 15
So CP of the Article = 100x =1500 Rs
Question : 4
4 years hence the sum of ages of A and B will be 16 years more than the sum of the present ages of B and C. 4 years ago the sum of A’s age and C’s age was 32 years, then what is the present age of C?
a) 18 years
b) 14 years
c) 10 years
d) 16 years
e) 12 years
Answer »Answer: (d)
According to the question:
Present age of A and C:
A + C = 40 ............(i)
After 4 years, sum of ages of A and B will be 16 years more than the sum of the present ages of B and C.
A + 4 + B + 4 = B + C + 16
A - C = 8 ............(ii)
On solving eq(i) and eq(ii).
2A = 48
A = 24
Then, the present age of C:
24 + C = 40
C = 16 Years
Question : 5
The ratio of speed of a boat in still water to speed of the current is 10 : 1. If ratio of the time taken by the boat to travel D km downstream to the time taken to travel (D – 45) km upstream is 3 : 2. Find the value of D.
a) 88
b) 54
c) 110
d) 99
e) 66
Answer »Answer: (d)
Let ratio of speed of a boat in still water to speed of the current is 10x : x,
then
$\text"D / ( 10+1 ) x" /\text "D - 45/ ( 10 - 1) x"$=$3/2$
⇒ 18D = 33D – 33 × 45
⇒ 15D = 33 × 45
⇒ D = 99
Question : 6
Train A crosses a vertical pole at the speed of 15 m/s in 20 seconds. Speed of train A is 3 m/s less than the speed of train B and length of train B is 30 meter less than length of train A. Find the time taken by Train B to cross 270 meter long platform.
a) 20 seconds
b) 15 seconds
c) 30 seconds
d) 45 seconds
e) 40 seconds
Answer »Answer: (c)
Let the length of Train A be L meters, then
According to question,
$L/15$= 20
⇒ L = 300 m
∴ Length of train A is 300 m
So, length of train B = 300 – 30 m = 270 meters
Speed of train B = 15 + 3 = 18 m/s
When B crosses a 270 m long platform,
Time = $\text"270 + 270"/18$ seconds = 30 seconds
Hence, the required time = 30 seconds.
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