IBPS RRB PO Prelims 12 sep 2020 Questions and Answers Detailed Explanation
MOST IMPORTANT previous year question answers - 1 EXERCISES
Directions:
In the following question two equations are given in variables X and Y. You have to solve these equations and determine the relation between X and Y.
The following question based on IBPS RRB PO topic of previous year question answers
(a) y > x
(b) y < x
(c) y ≥ x
(d) y ≤ x
e) x = y or no relation can be established
The correct answers to the above question in:
Answer: (b)
x2 – 11x + 30 = 0
x2 – 5x – 6x + 30 = 0
x(x – 5) – 6(x – 5) = 0
(x – 5)(x – 6) = 0
x = 6, 5
y2 + 12y + 36 = 0
y2 + 6y + 6y + 36 = 0
y(y + 6) + 6(y + 6) = 0
(y + 6)(y + 6) = 0
y = -6, -6
So, x > y.
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Read more ibps rrb po prelims 12 sep 2020 Based Previous Year Questions and Answers
Question : 1
I. x2 + 9x + 20 = 0 and II. 8y2 – 15y + 7 = 0
a) y > x
b) y < x
c) y ≥ x
d) y ≤ x
e) x = y or no relation can be established
Answer »Answer: (a)
x2 + 9x + 20 = 0
x2 + 4x + 5x + 20 = 0
x(x + 4) + 5(x + 4) = 0
(x + 5)(x + 4) = 0
x = – 4 , –5
8y2 – 15y + 7 = 0
8y2 – 8y – 7y + 7 = 0
8y(y – 1) – 7(y – 1) = 0
(8y – 7)(y – 1) = 0
y = $7/8$ , 1
So, y > x
Question : 2
I. x2 + 13x + 40 = 0 and II. y2 + 7y + 10 = 0
a) y > x
b) y < x
c) y ≥ x
d) y ≤ x
e) x = y or no relation can be established
Answer »Answer: (c)
x2 + 13x + 40 = 0
x2 + 8x + 5x + 40 = 0
x(x + 8) + 5 (x + 8) = 0
(x + 5) (x + 8) = 0
X = –5, – 8
y2 + 7y + 10 = 0
y2 + 2y + 5y + 10 = 0
y (y+2) + 3 (y + 2) = 0
y = – 2, – 5
so, y ≥ x
Question : 3
I. x2 – 20x + 91 = 0 and II. Y2 + 16y + 63 = 0
a) y > x
b) y < x
c) y ≥ x
d) y ≤ x
e) x = y or no relation can be established
Answer »Answer: (b)
x2 – 20 + 91 = 0
x2 – 13x – 7x + 91 = 0
x (x –13) – 7 ( x –13) = 0
(x –7) (x –13) = 0
X = 13, 7
Question : 4
I. x2 – x – 12 = 0 and II. y2 + 5y + 6 =0
a) y > x
b) y < x
c) y ≥ x
d) y ≤ x
e) x = y or no relation can be established
Answer »Answer: (e)
x2 – 4x + 3x – 12 = 0
x (x –4) + 3(x –4) = 0
(x +3) (x –4) = 0
X = – 3, 4
y2 + 5y + 6 = 0
y2 + 2y + 3y + 6 = 0
y (y + 2) + 3 (y + 2) = 0
(y+2)(y+3) = 0
y = – 2, – 3
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IBPS RRB PO Prelims 12 sep 2020
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