IBPS RRB PO Prelims 12 sep 2020 Questions and Answers Detailed Explanation
MOST IMPORTANT previous year question answers - 1 EXERCISES
The following question based on IBPS RRB PO topic of previous year question answers
(a) Rs. 11200
(b) Rs. 5600
(c) Rs. 12600
(d) Rs. 12000
e) None of these
The correct answers to the above question in:
Answer: (d)
Let sum be Rs P
Using the data provided in the question, we get
1320 = $\text"P x 13 x 5"/100 - \text"P x 9 x 6"/100$
On solving the equation, we get
P = Rs. 12000
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Read more ibps rrb po prelims 12 sep 2020 Based Previous Year Questions and Answers
Question : 1
Two classes A and B have 320 and 240 students respectively. If the percentage of students, who didn’t pass in classes A and B are 40% and 30% respectively, what is the total number of failed students?
a) 400
b) 360
c) 320
d) 260
e) 200
Answer »Answer: (e)
Number of students who failed in class A
= 30 × 0.4 = 128
Number of students who failed in class B
= 240 × 0.3 = 72
Total numbers of failed students
= 128 + 72 = 200
Hence, the answer is E.
Question : 2
A and B together take 6 days to complete a work. If it is given that A takes 9 days less than B to complete the work alone, then in how many days B alone will complete the work?
a) 18
b) 15
c) 12
d) 9
e) 8
Answer »Answer: (a)
Let the minimum of days taken by B alone to complete the work be x days.
Number of days taken day A alone to complete the work
= x – 9 days
$1/x + 1/\text"x - 9" = 1/6$
$\text"x(x - 9)"/\text"2x - 9" = 6$
x2 - 9x = 12x - 54
x2 - 21x + 54 = 0
x2 - 18x -3x + 54 = 0
x(x - 18) -3(x - 18) = 0
(x - 3)(x - 18) = 0
x = 3 , 18
X cannot be 3 as the number of days can’t be negative for any person
x = 18 days
Number of days taken by B alone = x = 18 days
Hence, the answer is A.
Directions:
Read the chart carefully and answer the following questions.
Given pie-chart shows the percentage distribution of total items sold by six Indian companies in any year.
![IBPS RRB PO Prelims 2020](/adminicon/bunch/images/ibps-rrb-po-prelims-12-sep-66-70a.png)
Question : 3
If items manufactured by Pakistan is 50400 which is 20% more than items manufactured by India, then nd difference of items sold by C and E?
a) 2600
b) 2400
c) 1800
d) 1600
e) 2100
Answer »Answer: (e)
items manufactured by India = 50400 x $100/120$ = 42000
Required Difference = 42000 x $\text"17 - 12"/100$
= 2100
Question : 4
In a 140 litres of a mixture of milk and water, the ratio of milk to water is 5 : 2. If 28 litres mixture is taken out and same amount of water is added to the mixture. If this process is repeated for two times, then what will be quantity of milk in nal mixture?
a) 81.48 litres
b) 64.84 litres
c) 51.2 litres
d) 51.68 litres
e) 65.68 litres
Answer »Answer: (c)
Initial quantity of milk = $5/1$ × 140 = 100 litres
And that of water = 140 – 100 = 40 litres
Final quantity of mixture = 100 × $(1 - 20/100)^3$ = 51.2 litres
Question : 5
Sandeep sold an article at a profit of 13$1/3$% at its selling price to Vinod. Vinod further sold it at 7.5% loss for Rs. 1110. Find the difference in the original cost price of that article and selling price of article for Vinod?
a) Rs. 92
b) Rs. 84
c) Rs. 60
d) Rs. 50
e) Rs. 70
Answer »Answer: (e)
Prot% = 13$1/3$% = $2/15$
Let the selling price of that article be Rs. 15X
Profit = Rs. 2X
Cost price = Rs. 13X
Using the data provided in the question, we get
15X × 92.5% = 1110
X = 80
Cost price = 13X = Rs. 1040
Required difference = 1110 - 1040
= Rs. 70
Directions:
Read the following table carefully and answer the given questions.
In the table, data of number of members participating in an event from 6 sports clubs – A, B, C, D, E and F.
Sports club | Total no. of members | % of members participated |
A | 4000 | 65% |
B | 9000 | 20% |
C | 4800 | 25% |
D | 5000 | 30% |
E | 6000 | 35% |
F | 6750 | 40% |
Question : 6
If the 30% of the members participated in the event from the sports club B played badminton and rest played Hockey, Cricket and Football in the ratio 2 : 4 : 3, then the number of members, who played Football is
a) 380
b) 420
c) 460
d) 480
e) 500
Answer »Answer: (b)
The number of members of sports club B, who participated in the event = 20% of 9000 = 1800
The number of members of sports club B, who played Badminton
= 30% of 1800 = 540
Hence, the number of members of sports club B, who played Football
= $3/\text"(2 + 4 + 3)"$ × (1800 – 540) = 420.
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