IBPS RRB PO Prelims 12 sep 2020 Questions and Answers Detailed Explanation
MOST IMPORTANT previous year question answers - 1 EXERCISES
Directions:
Read the following table carefully and answer the given questions.
In the table, data of number of members participating in an event from 6 sports clubs – A, B, C, D, E and F.
| Sports club | Total no. of members | % of members participated |
| A | 4000 | 65% |
| B | 9000 | 20% |
| C | 4800 | 25% |
| D | 5000 | 30% |
| E | 6000 | 35% |
| F | 6750 | 40% |
The following question based on IBPS RRB PO topic of previous year question answers
(a) 380
(b) 420
(c) 460
(d) 480
e) 500
The correct answers to the above question in:
Answer: (b)
The number of members of sports club B, who participated in the event = 20% of 9000 = 1800
The number of members of sports club B, who played Badminton
= 30% of 1800 = 540
Hence, the number of members of sports club B, who played Football
= $3/\text"(2 + 4 + 3)"$ × (1800 – 540) = 420.
Discuss Form
Read more ibps rrb po prelims 12 sep 2020 Based Previous Year Questions and Answers
Question : 1
Sandeep sold an article at a profit of 13$1/3$% at its selling price to Vinod. Vinod further sold it at 7.5% loss for Rs. 1110. Find the difference in the original cost price of that article and selling price of article for Vinod?
a) Rs. 92
b) Rs. 84
c) Rs. 60
d) Rs. 50
e) Rs. 70
Answer »Answer: (e)
Prot% = 13$1/3$% = $2/15$
Let the selling price of that article be Rs. 15X
Profit = Rs. 2X
Cost price = Rs. 13X
Using the data provided in the question, we get
15X × 92.5% = 1110
X = 80
Cost price = 13X = Rs. 1040
Required difference = 1110 - 1040
= Rs. 70
Question : 2
In a 140 litres of a mixture of milk and water, the ratio of milk to water is 5 : 2. If 28 litres mixture is taken out and same amount of water is added to the mixture. If this process is repeated for two times, then what will be quantity of milk in nal mixture?
a) 81.48 litres
b) 64.84 litres
c) 51.2 litres
d) 51.68 litres
e) 65.68 litres
Answer »Answer: (c)
Initial quantity of milk = $5/1$ × 140 = 100 litres
And that of water = 140 – 100 = 40 litres
Final quantity of mixture = 100 × $(1 - 20/100)^3$ = 51.2 litres
Question : 3
Ashutosh lends two equal sums, one at the rate of 13% per annum for ve years and the other at the rate of 9% per annum for six years, both at simple interest. If the difference in interest accrued in the two cases is Rs 1320. Find the sum.
a) Rs. 11200
b) Rs. 5600
c) Rs. 12600
d) Rs. 12000
e) None of these
Answer »Answer: (d)
Let sum be Rs P
Using the data provided in the question, we get
1320 = $\text"P x 13 x 5"/100 - \text"P x 9 x 6"/100$
On solving the equation, we get
P = Rs. 12000
Question : 4
What is the difference of the number of members participated in the event from the sports clubs B and C and the number of members not participated in the event from the sports clubs D and E?
a) 7400
b) 2400
c) 3600
d) 4400
e) 3000
Answer »Answer: (d)
The number of members of sports club B, who participated in the event
= 20% of 9000 = 1800
The number of members of sports club C, who participated in the event
= 25% of 4800 = 1200
The number of members of sports club D, who did not participate in the event
= (100 – 30)% of 5000 = 3500
The number of members of sports club E, who did not participate in the event
= (100 – 35)% of 6000 = 3900
then required difference = (3500 + 3900) – (1800 + 1200)
= 4400.
Question : 5
What is the average number of members not participated in the event from the sports clubs A, B, D, E and F?
a) 3990
b) 3610
c) 4060
d) 3570
e) 4010
Answer »Answer: (e)
The number of members of sports club A, who did not participate in the event
= (100 – 65)% of 4000
= 35% of the 4000 = 1400
The number of members of sports club B, who did not participate in the event
= (100 – 20)% of 9000 = 7200
The number of members of sports club D, who did not participate in the event
= (100 – 30)% of 5000 = 3500
The number of members of sports club E, who did not participate in the event
= (100 – 35)% of 6000 = 3900
The number of members of sports club F, who did not participate in the event
= (100 – 40)% of 6750 = 4050
Hence, the required average
= $\text"1400 + 7200 + 3500 + 3900 + 4050"/5$ = 4010.
Question : 6
Number of members of the sports club A, who did not participate in the event is what percent more/less than that of sports club D?
a) 40%
b) 60%
c) 28%
d) 35%
e) 55%
Answer »Answer: (b)
The number of members of sports club A, who did not participate in the event
= (100 – 65)% of 4000
= 35% of the 4000 = 1400
The number of members of sports club D, who did not participate in the event
= (100 – 30)% of 5000
= 70% of the 5000 = 3500
Hence, the required percent = $\text"3500 - 1400"/3500$ × 100 = 60%.
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