IBPS RRB clerk 19 sep 2020 Questions and Answers Detailed Explanation
MOST IMPORTANT previous year question answers - 1 EXERCISES
The following question based on IBPS RRB Clerk topic of previous year question answers
(a) Rs. 200
(b) Rs. 240
(c) Rs. 300
(d) Rs. 450
e) Rs. 600
The correct answers to the above question in:
Answer: (c)
Let the cost price of the article = Rs. 100x, then
Marked price of the article = 100x + 50% of 100x = Rs. 150x
The selling price of the article = Rs. (150x – 50)
According to question
Profit = SP – CP
50 = (150x – 50) – 100x
⇒ 50 = 50x – 50
⇒ 50x = 100
⇒ x = 2
Hence, the marked price of the article = Rs. 150x
= 150 × 2
= Rs. 300.
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Read more ibps rrb clerk prelims 19 sep 2020 Based Previous Year Questions and Answers
Question : 1
A boat travels upstream at the speed of 10 km/hr for t hours and downstream at the speed of 14 km/hr for 6 hours. If the distance travelled in downstream direction is 44 km more than that in upstream direction, then what is the value of t?
a) 7
b) 2
c) 3
d) 4
e) 6
Answer »Answer: (d)
Distance = Speed × Time
The distance travelled in downstream direction
= 14 × 6 = 84 km
The distance travelled in upstream direction
= 10 × t = 10t km
According to question
84 – 10t = 44
⇒ 10t = 84 – 44 = 40
⇒ t = $40/10$ = 4
Question : 2
A and B start a business by investing Rs. X and Rs. (X + 800) respectively. After 1 year, A earned a profit of Rs. 3200 out of the total profit of Rs. 6800, then what is the value of X?
a) 3200
b) 4000
c) 6400
d) 7200
e) 8000
Answer »Answer: (c)
As both A and B invested for the same time period, then
The ratio of their profit = Ratio of their investment
$X/3200 = \text"X + 800"/\text"6800 - 3200"$
$X/3200 = \text"X + 800"/\text"3600"$
⇒ 9X = 8(X + 800)
⇒ X = 8 × 800 = 6400
Question : 3
The circumference of a circle is 2 cm more than the perimeter of the rectangle and the length of the rectangle is equal to the diameter of the circle. If the breadth of the rectangle is half of the diameter of the circle, what is the radius of the circle?
a) 7 cm
b) 2 cm
c) 4 cm
d) 14 cm
e) 21 cm
Answer »Answer: (a)
Let the radius of the circle = r cm, then
Length of the rectangle = Diameter of circle = 2r cm
The breadth of the rectangle = Half of the diameter of circle = r cm
According to question
Circumference of a circle – Perimeter of rectangle = 2 cm
2πr– 2(2r + r) = 2
⇒ πr – 3r = 1
⇒ r($22/7$ – 3) = 1
⇒ r = 7
Directions:
Read the data carefully and answer the questions.
The table given below shows the data of the number of clothes dry cleaned by four different shops - L, M, N and O on the five working days - Monday, Tuesday, Wednesday, Thursday and Friday.
Shop/Days | Monday | Tuesday | Wednesday | Thursday | Friday |
L | 50 | 60 | 85 | 25 | 110 |
M | 80 | 75 | 95 | 120 | 105 |
N | 100 | 55 | 35 | 60 | 45 |
O | 40 | 90 | 60 | 115 | 70 |
Question : 4
What is the number of shops who dry cleaned more number of clothes than O on all the days put together?
a) 0
b) 1
c) 2
d) 3
e) Cannot be determined
Answer »Answer: (b)
Number of clothes dry cleaned by L on all the days put together
= 50 + 60 + 85 + 25 + 110 = 330
Similarly, for all the shop's total number of clothes dry cleaned on all the days is calculated and it is shown in the table below:
Shop/Days | Monday | Tuesday | Wednesday | Thursday | Friday | Total |
L | 50 | 60 | 85 | 25 | 110 | 330 |
M | 80 | 75 | 95 | 120 | 105 | 475 |
N | 100 | 55 | 35 | 60 | 45 | 295 |
D | 40 | 90 | 60 | 115 | 70 | 375 |
Question : 5
Which of the following days had the most number of clothes dry cleaned by all the shops together?
a) Monday
b) Tuesday
c) Wednesday
d) Thursday
e) Friday
Answer »Answer: (e)
Total number of clothes dry cleaned by all the shops together on Monday
= 50 + 80 + 100 + 40 = 270
Similarly, for all the day's total number of clothes dry cleaned by all the shops is calculated and it is shown in the table below:
Shop/Days | Monday | Tuesday | Wednesday | Thursday | Friday |
L | 50 | 60 | 85 | 25 | 110 |
M | 80 | 75 | 95 | 120 | 105 |
N | 100 | 55 | 35 | 60 | 45 |
D | 40 | 90 | 60 | 115 | 70 |
The most number of clothes were dry cleaned on Friday. Hence, the answer is option E.
Question : 6
The sum of the number of clothes dry cleaned by N on Tuesday, Wednesday and Thursday is what percentage of the clothes dry cleaned by O on all the days?
a) 30%
b) 40%
c) 50%
d) 55%
e) 60%
Answer »Answer: (b)
Sum of the number of clothes dry cleaned by N on Tuesday, Wednesday and Thursday
= 55 + 35 + 60 = 150
Clothes dry cleaned by O on all the days
= 40 + 90 + 60 + 115 + 70
= 375
Required percentage = $150/375$ × 100 = 40 %
Hence, the answer is option B.
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