IBPS PO Prelims 3 oct 2020 Questions and Answers Detailed Explanation
MOST IMPORTANT previous year question answers - 1 EXERCISES
The following question based on IBPS PO topic of previous year question answers
(a) Rs. 96000
(b) Rs. 80000
(c) Rs. 48000
(d) Rs. 60000
e) None of these
The correct answers to the above question in:
Answer: (e)
In 8 years, he gets 16% as interest, then
In 4 years, he will get = 8% as interest
According to question
8% ≡ Rs. 9600
⇒ 1% ≡ Rs. 1200
⇒ 100% ≡ Rs. 120000
Hence, the sum = 100% ≡ Rs. 120000.
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Read more ibps po prelims 3 oct 2020 Based Previous Year Questions and Answers
Directions:
Study the following information carefully and answer the questions given below.
In the table, percentage of shirts (formal and casual) sold out of the total number of shirts sold in the week and number of casual shirts sold data related to the number of shirts sold on ve week days – Monday, Tuesday, Wednesday, Thursday and Friday are given.
Total number of shirts sold in the week = x
Day | Percentage of total shirts sold | Number of casual shirts sold |
Monday | 14% | 32 |
Tuesday | 16% | 24 |
Wednesday | 12% | 28 |
Thursday | 22% | 56 |
Friday | 18% | 20 |
Note: Total number of shirts sold on Saturday and Sunday together = 72
Question : 1
What is the average number of total shirts sold on Wednesday, Friday, Saturday and Sunday together?
a) 64
b) 24
c) 36
d) 48
e) None of these
Answer »Answer: (d)
Total number of shirts sold on weekdays
= (14 + 16 + 12 + 22 + 18)% of x
= 82% of x
Total number of shirts sold on weekends
= (100 – 82)% of x
= 18% of x
According to the question
18% of x = 72
⇒ x = 400
Number of formal shirts sold = Total number of shirts sold – Number of casual shirts sold
Day | Percentage of total shirts sold | Total number of casual shirts sold | Number of formal shirts sold |
Monday | 14% | 32 | 24 |
Tuesday | 16% | 24 | 40 |
Wednesday | 12% | 28 | 20 |
Thursday | 22% | 56 | 32 |
Friday | 18% | 20 | 52 |
The average number of total shirts sold on Wednesday, Friday, Saturday and Sunday together
=$\text"(28+20) + (20+52) + 72"/4$ = 48
Question : 2
What is the sum of the formal shirts sold on Monday, Tuesday and Wednesday together?
a) 102
b) 168
c) 84
d) 64
e) None of these
Answer »Answer: (c)
Total number of shirts sold on weekdays
= (14 + 16 + 12 + 22 + 18)% of x
= 82% of x
Total number of shirts sold on weekends
= (100 – 82)% of x
= 18% of x
According to the question
18% of x = 72
⇒ x = 400
Number of formal shirts sold = Total number of shirts sold – Number of casual shirts sold
Day | Percentage of total shirts sold | Total number of casual shirts sold | Number of formal shirts sold |
Monday | 14% | 32 | 24 |
Tuesday | 16% | 24 | 40 |
Wednesday | 12% | 28 | 20 |
Thursday | 22% | 56 | 32 |
Friday | 18% | 20 | 52 |
The sum of the formal shirts sold on Monday, Tuesday and Wednesday together
= 24 + 40 + 20 = 84
Question : 3
What is the ratio of the number of casual shirts sold on Monday and Wednesday together and a number of formal shirts sold on Tuesday and Thursday together?
a) 4 : 3
b) 3 : 4
c) 5 : 3
d) 6 : 5
e) None of these
Answer »Answer: (e)
Total number of shirts sold on weekdays
= (14 + 16 + 12 + 22 + 18)% of x
= 82% of x
Total number of shirts sold on weekends
= (100 – 82)% of x
= 18% of x
According to the question
18% of x = 72
⇒ x = 400
Number of formal shirts sold = Total number of shirts sold – Number of casual shirts sold
Day | Percentage of total shirts sold | Total number of casual shirts sold | Number of formal shirts sold |
Monday | 14% | 32 | 24 |
Tuesday | 16% | 24 | 40 |
Wednesday | 12% | 28 | 20 |
Thursday | 22% | 56 | 32 |
Friday | 18% | 20 | 52 |
The number of casual shirts sold on Monday and Wednesday together
= 32 + 28 = 60
The number of formal shirts sold on Tuesday and Thursday together
= 40 + 32 = 72
Hence, the required ratio = 60 : 72
= 5 : 6
Question : 4
Running at the speed of 3 km/hr, a person reaches his destination 10 minutes later than usual time. if he increases his speed by 1 km/hr, he reaches his destination 15 min earlier. nd the distance to his destination.
a) 10 km
b) 12 km
c) 5 km
d) 4 km
e) None of these
Answer »Answer: (c)
Let the distance to his destination be d km, then
According to question we get,
$d/3$ – $d/(3+1) = \text"10+15"/60$
⇒$d/3$ – $d/4 = 5/12$
⇒$d/12 = 5/12$
⇒ d = 5
Hence, the distance to his destination = d = 5 km
Question : 5
4 years hence, the ratio of ages A and B will be 5 : 7 and 6 years hence, the ratio of ages will be 11 : 15, then nd their present ages.
a) 20 years, 26 years
b) 16 years, 24 years
c) 18 years, 28 years
d) 12 years, 18 years
e) None of these
Answer »Answer: (b)
Let the present ages of A and B be a years and b years, then
According to question
$\text"a+4"/5=\text"b+4"/7$
⇒ 7a – 5b = –8 …. (i)
And
$\text"a+6"/11=\text"b+6"/15$
⇒ 15a – 11b = –24 …. (ii)
On solving equations (i) and (ii), we get
a = 16 and b = 24
Hence, the ages of A and B will be 16 years and 24 years respectively.
Question : 6
A and B together can do a piece of work in 12 days, A and C together can do the same work in 15 days. If B and C together can do the same work in 20 days, then in how many days A, B and C together can complete the same work?
a) 8
b) 6
c) 10
d) 9
e) None of these
Answer »Answer: (c)
Let the total work = 60 (LCM of 12, 15 and 20)
Efciency of A and B together = $60/12$ = 5
Efciency of B and C together = $60/20$ = 3
Efciency of C and A together = $60/15$ = 4
So, efciency of A, B and C together = $\text"5+3+4"/2$ = 6
Hence, the required number of days = $60/6$ = 10 days.
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