RBI assistant prelims (14 feb) 2020 - Category wise Question and Answer Practice Test with Solutions & PDF
RBI assistant PRACTICE TEST [1 - EXERCISES]
RBI assistant prelims (14 feb) 2020
Question : 81 [RBI-assistant-2020]
Average of 10 observation in a series is 64. If average of first 5 observation is 45 and last 3 observation is 71 . Find the average of remaining 2
a) 91
b) 103
c) 101
d) 111
Answer »Answer: (c)
Required average
$= \text"10 x 64 - 5 x 45 - 3 x 71"/2$
$= \text"640 - 225 - 213"/2$
= 101
Question : 82 [RBI-assistant-2020]
Side of a square is equal to the diameter of a circle. What is the perimeter of square, if area of circle is 616 cm2?
a) 116 cm
b) 124 cm
c) 112 cm
d) 120 cm
e) 132 cm
Answer »Answer: (c)
Radius of the circle = $√{616/π}$
= $√{\text"616 x 7"/22}$
= $√196$
= 14 cm
⇒ Side of the square = 2 × Radius
= 2 × 14 = 28 cm
Hence, the perimeter of the square = 4 × Side of the square
= 4 × 28 = 112 cm.
Question : 83 [RBI-assistant-2020]
Ram and Shyam started a business with initial investments of Rs. 1000 and Rs. 2000 respectively. After few months Ram left the business. If at the end of the year the ratio of profits of Ram and Shyam is 1 : 4, then find the number of months Ram was in business.
a) 6
b) 2
c) 4
d) 3
e) 8
Answer »Answer :(a)
Let Ram left the business after x months, then
= $\text"1000 x X"/1 = \text"2000 x 12"/4$
⇒ x = 6
Question : 84 [RBI-assistant-2020]
Ajay spends 20% of his monthly salary on rent. He spends 40% of remaining on other expenses. If his expenditure on the other expenses is Rs. 9600, then find his expenditure on rent.
a) Rs. 12,000
b) Rs. 6,500
c) Rs. 9,000
d) Rs. 6,000
Answer »Answer: (d)
Let his monthly salary = 100x, then
Expense on rent = 20x
Expense on other expenses = 40% of (100 – 20)x
= 40% of 80x = 32x
According to question,
32x ≡ Rs. 9600
⇒ x ≡ Rs. 300
Hence, his expenditure on hours rent = 20x
⇒20 × Rs. 300
⇒ Rs. 6000.
Question : 85 [RBI-assistant-2020]
A, B and C are 3 positive integers such that A is 20% less than C and C is 50% more than B. If sum of A, B and C is 111, then find the value of B
a) 32
b) 20
c) 30
d) 40
e) 36
Answer »Answer: (c)
C = B + 50% of B = 1.5 B
A = C – 20% of C = C – 0.2C = 0.8 C = 0.8 × 1.5 B = 1.2 B
According to question,
A + B + C = 111
⇒ 1.2B + B + 1.5B = 111
⇒ 3.7B = 111
⇒ B = 30
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